∣4−31∣=
\( |4 - 3^1| = \)
\( |3^3 - 5| = \)
\( |5^2 - 24| = \)
\( |6^2 - 10| = \)
\( |3^2 - 7| = \)
First, calculate :
.
Then, subtract 3 from 4:
.
The absolute value of 1 is 1, so the expression evaluates to 1. Therefore, |4 - 3^1| = 1.
First, calculate . That is, .
Next, subtract 5 from 27: .
Finally, the absolute value of 22 is since it is already a positive number.
First, calculate . That is, .
Next, subtract 24 from 25: .
Finally, the absolute value of 1 is since it is already a positive number.
First, calculate . That is, .
Next, subtract 10 from 36: .
Finally, the absolute value of 26 is since it is already a positive number.
The expression inside the absolute value is . Calculate :
.
Then, subtract 7 from 9:
.
The absolute value of 2 is 2, so the expression evaluates to 2. Therefore, |3^2 - 7| = 2.
\( \left|2^3 - 5\right| = \)
\( \left|(9 - 3)^2\right| = \)
The expression represents the absolute value of the result of subtracting 5 from .
Calculate the power: .
Subtract the numbers: .
The absolute value of 3 is , so the answer is .
The expression represents the absolute value of the square of (9 - 3).
Calculate the difference: .
Then compute the square: .
The absolute value of is .