Divisibility Rules for 2, 4 and 10: Identify which of the numbers is divisible by?

To determine which number is divisible by 4, we will apply the divisibility rule for 4:

• A number is divisible by 4 if the number formed by its last two digits is divisible by 4.

Let's check each option:

For number 4433, the last two digits are 33:
33 is not divisible by 4 since $33 \div 4 = 8.25$.
Thus, 4433 is not divisible by 4.

For number 3434, the last two digits are 34:
34 is not divisible by 4 since $34 \div 4 = 8.5$.
Thus, 3434 is not divisible by 4.

For number 3624, the last two digits are 24:
24 is divisible by 4 since $24 \div 4 = 6$.
Thus, 3624 is divisible by 4.

For number 3621, the last two digits are 21:
21 is not divisible by 4 since $21 \div 4 = 5.25$.
Thus, 3621 is not divisible by 4.

Therefore, the number that is divisible by 4 is $3624$.

To solve this problem, we'll follow these steps:

• Step 1: Apply the divisibility rule for 4.
• Step 2: Check the last two digits of each number.
• Step 3: Determine if the last two digits form a number divisible by 4.

Now, let's work through each step:

Step 1: The divisibility rule for 4 states that a number is divisible by 4 if its last two digits form a number that is divisible by 4.

Step 2: Examine the last two digits of each number:
- For 11141, the last two digits are 41.
- For 13240, the last two digits are 40.
- For 10051, the last two digits are 51.
- For 10041, the last two digits are 41.

Step 3: Check divisibility by 4:
- 41 is not divisible by 4.
- 40 is divisible by 4 (since $40 \div 4 = 10$ exactly with no remainder).
- 51 is not divisible by 4.
- 41 is not divisible by 4.

Therefore, the number that is divisible by 4 is 13240.

To solve this problem, we need to determine which of the numbers is divisible by 4. We'll apply the divisibility rule for 4, which states that a number is divisible by 4 if the last two digits of the number form a value divisible by 4.

Let's check each number:

• For 130, the last two digits are 30. $\frac{30}{4} = 7.5$ (not an integer), so 130 is not divisible by 4.
• For 160, the last two digits are 60. $\frac{60}{4} = 15$ (an integer), so 160 is divisible by 4.
• For 150, the last two digits are 50. $\frac{50}{4} = 12.5$ (not an integer), so 150 is not divisible by 4.
• For 170, the last two digits are 70. $\frac{70}{4} = 17.5$ (not an integer), so 170 is not divisible by 4.

Therefore, the solution to the problem is $\text{160}$, as it is the only number in the list divisible by 4.

To determine which numbers are divisible by 4, we apply the divisibility rule for 4: a number is divisible by 4 if its last two digits form a number divisible by 4.

Let's check each number:

• 4747: The last two digits are 47. Check divisibility: $47 \div 4 \neq 0 \,(\text{remainder 3})$. Not divisible by 4.
• 4242: The last two digits are 42. Check divisibility: $42 \div 4 \neq 0 \,(\text{remainder 2})$. Not divisible by 4.
• 3030: The last two digits are 30. Check divisibility: $30 \div 4 \neq 0 \,(\text{remainder 2})$. Not divisible by 4.
• 5151: The last two digits are 51. Check divisibility: $51 \div 4 \neq 0 \,(\text{remainder 3})$. Not divisible by 4.

Since none of the numbers listed are divisible by 4 based on this rule, the correct answer is None of the above.

To solve this problem, we'll examine each number to determine which is divisible by 2 by looking at its last digit.

• 5055: The last digit is 5, which is odd. Therefore, 5055 is not divisible by 2.

• 3415: The last digit is 5, which is odd. Therefore, 3415 is not divisible by 2.

• 6895: The last digit is 5, which is odd. Therefore, 6895 is not divisible by 2.

• 2188: The last digit is 8, which is even. Therefore, 2188 is divisible by 2.

By applying the rule of divisibility by 2, we find that the number 2188 is divisible by 2.

Let's analyze which number from the list is divisible by 2:

• The number 4213 ends in 3, which is not even.
• The number 4217 ends in 7, which is not even.
• The number 4212 ends in 2, which is even.
• The number 4215 ends in 5, which is not even.

By the divisibility rule for 2, a number is divisible by 2 if and only if its last digit is one of these: 0, 2, 4, 6, or 8.

Checking the numbers given, only 4212 has an even last digit, which is 2.

Thus, the number $4212$ is the one divisible by 2.

To solve this problem, we will use the divisibility rule for 2, which states that a number is divisible by 2 if its last digit is an even number. Even numbers include 0, 2, 4, 6, and 8.

Let's analyze each of the given numbers:

• 1006: The last digit is 6. Since 6 is an even number, 1006 is divisible by 2.
• 1005: The last digit is 5. 5 is not even, so 1005 is not divisible by 2.
• 1007: The last digit is 7. 7 is not even, so 1007 is not divisible by 2.
• 1003: The last digit is 3. 3 is not even, so 1003 is not divisible by 2.

Therefore, among the given options, the only number divisible by 2 is 1006.

The correct choice is 1006.

To solve this problem, we'll use the divisibility rule for 2. According to this rule, a number is divisible by 2 if its last digit is an even number (0, 2, 4, 6, or 8). We will apply this rule to each of the given numbers:

• 2148: The last digit is 8, which is an even number. Therefore, 2148 is divisible by 2.
• 2131: The last digit is 1, which is not an even number. Therefore, 2131 is not divisible by 2.
• 2515: The last digit is 5, which is not an even number. Therefore, 2515 is not divisible by 2.
• 6425: The last digit is 5, which is not an even number. Therefore, 6425 is not divisible by 2.

By applying the divisibility rule for 2, we find that 2148 is the only number divisible by 2 from the given choices.

To solve this problem, we'll follow these steps:

• Step 1: Identify the divisibility rule for 10.
• Step 2: Check the last digit of each given number.
• Step 3: Determine which number meets the divisibility condition.

Now, let's work through each step:
Step 1: A number is divisible by 10 if its last digit is 0. Therefore, we will check the last digit of each number provided.
Step 2: Let's inspect the last digits:
- Number 3310 ends in 0.
- Number 115 ends in 5.
- Number 212 ends in 2.
- Number 1341 ends in 1.
Step 3: According to the divisibility rule for 10, only the number 3310 ends with the digit 0, making it divisible by 10.

Therefore, the solution to the problem is 3310.

To solve this problem, we'll follow these steps:

• Step 1: Identify the numbers given: 10510, 10024, 14521, 1245.
• Step 2: Apply the divisibility rule for 10.
• Step 3: Check the last digit of each number to see which is divisible by 10.

Now, let's work through each step:
Step 1: The numbers we need to check are 10510, 10024, 14521, and 1245.
Step 2: The rule for divisibility by 10 states that a number is divisible by 10 if its last digit is 0.
Step 3: We check each number:
  10510 ends in 0 (it is divisible by 10).
  10024 ends in 4 (not divisible by 10).
  14521 ends in 1 (not divisible by 10).
  1245 ends in 5 (not divisible by 10).

Therefore, the solution to the problem is 10510.

To solve this problem, we'll determine which number from the given choices is divisible by 10 by checking the last digit of each number:

• 2143: The last digit is 3.
• 2149: The last digit is 9.
• 2150: The last digit is 0.
• 2151: The last digit is 1.

According to the divisibility rule for 10, a number is divisible by 10 only if its last digit is 0. Among these choices, only 2150 has a last digit of 0.

Therefore, the solution to the problem is $2150$.

To solve this problem, let's apply the divisibility rule for 10:

• A number is divisible by 10 if its last digit is 0.

We have the following numbers: 55, 50, 52, and 51. Let's check each one:

Examining the numbers:

• 55: The last digit is 5. This is not 0, so 55 is not divisible by 10.
• 50: The last digit is 0. Thus, 50 is divisible by 10.
• 52: The last digit is 2. This is not 0, so 52 is not divisible by 10.
• 51: The last digit is 1. This is not 0, so 51 is not divisible by 10.

Hence, the number 50 is divisible by 10.

Therefore, the correct choice is choice 2: 50.