Perimeter of a Triangle: Applying the formula

The perimeter of the triangle is equal to the sum of all sides together, therefore:

$6+8+10=14+10=24$

The perimeter of a triangle is equal to the sum of all its sides together:

$11+7+13=11+20=31$

To solve this problem, we'll follow these steps:

• Step 1: Identify the given information.
• Step 2: Apply the perimeter formula for a triangle.
• Step 3: Perform the addition to find the perimeter.

Now, let's work through each step:

Step 1: We have the lengths of the sides of $\triangle ABC$ as follows:
$AB = 7$, $BC = 14$, and $CA = 8$.

Step 2: We'll use the formula for the perimeter of a triangle, which is the sum of its side lengths:
$P = AB + BC + CA$.

Step 3: Plugging in the values, we calculate:
$P = 7 + 14 + 8 = 29$.

Therefore, the perimeter of $\triangle ABC$ is $\textbf{29}$.

To find the perimeter of triangle $\triangle ABC$, we need to sum the lengths of its sides:

• Side $AB = 3$
• Side $BC = 4$
• Side $CA = 5$

Using the formula for the perimeter of a triangle:

$\text{Perimeter} = AB + BC + CA$

Substitute the known values:

$\text{Perimeter} = 3 + 4 + 5$

$\text{Perimeter} = 12$

Thus, the perimeter of triangle $\triangle ABC$ is $\mathbf{12}$.

From the multiple-choice options provided, the correct choice is option 1: 12.

Since the triangle is equilateral, that is, all sides are equal to each other.

The perimeter of the triangle is equal to the sum of all sides together, the perimeter of the triangle in the drawing is equal to:

$5+5+5=15$

Since we are referring to an isosceles triangle, the two legs are equal to each other.

In the drawing, they give us the base which is equal to 4 and one side is equal to 6, therefore the other side is also equal to 6.

The perimeter of the triangle is equal to the sum of the sides and therefore:

$6+6+4=12+4=16$

Due to the fact that the the triangle is isosceles, its two legs are equal to one another.

Therefore, the base is 7 and the other two sides are 12.

The perimeter of a triangle is equal to the sum of all the sides together:

$12+12+7=24+7=31$

The problem requires us to calculate the perimeter of triangle ABC with given side lengths. To solve this:

• Step 1: Identify the given side lengths
  According to the given information:
  $AB = 10$
  $BC = 5.6$
  $CA = 4$
• Step 2: Apply the perimeter formula
  The formula for the perimeter $P$ of a triangle is: $P = AB + BC + CA$
• Step 3: Perform the calculation
  Plugging in the values, $P = 10 + 5.6 + 4 = 19.6$

Therefore, the perimeter of triangle ABC is $19.6$.