Rearrange the following digits to create a number divisible by 2:
2, 1, and 3.
We have hundreds of course questions with personalized recommendations + Account 100% premium
Rearrange the following digits to create a number divisible by 2:
2, 1, and 3.
To solve this problem, let's explore how to form a number divisible by 2 using the digits 2, 1, and 3. A number is divisible by 2 if the last digit is an even number, which, from our given digits, is only the digit 2.
Let's examine all possible permutations of these digits and identify which numbers are divisible by 2:
From our examination, the numbers 132 and 312 both end in 2, making them divisible by 2. Therefore, the correct choice according to the problem's options is to select both permutations that satisfy the condition.
Therefore, the solution to the problem is Answer b and c.
Answer b and c.
Is the number 10 divisible by 4?
The divisibility rule for 2 depends on place value! Only the units place determines if a number is even or odd. For example, 321 has even digit 2, but it's odd because it ends in 1.
Yes! With digits 1, 2, 3, there are 6 possible arrangements: 123, 132, 213, 231, 312, 321. List them systematically to avoid missing any.
The same rule applies! Focus on arrangements that end in even digits. With digits 1, 2, 3, 4, you'd look for numbers ending in 2 or 4.
Absolutely! Numbers like 132 and 518 are divisible by 2 even though they contain odd digits. Only the last digit needs to be even (0, 2, 4, 6, or 8).
Think of it as the "even ending" rule! If a number ends in an even digit (0, 2, 4, 6, 8), it's divisible by 2. This is the same as asking "Is this number even or odd?"
Get unlimited access to all 18 Division - Advanced questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime