What is the area of a pool that has a length of meters and a width of of a meter?
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What is the area of a pool that has a length of meters and a width of of a meter?
To solve this problem, we need to find the area of a pool with a given length and width.
First, let's convert the length from a mixed number to an improper fraction. The length is meters, which can be written as an improper fraction:
The width is already given as a fraction: meters.
Step 2: To find the area of the pool, we multiply the length by the width:
Now, multiply the numerators together and the denominators together:
Step 3: Let's simplify . The greatest common divisor of 22 and 6 is 2, so dividing the numerator and the denominator by 2 gives:
This can be further expressed as a mixed number:
Therefore, the area of the pool is square meters.
\( \frac{1}{4}\times\frac{3}{2}= \)
Converting to makes multiplication much easier! You can't directly multiply a mixed number by a fraction without converting first.
Multiply the whole number by the denominator, then add the numerator:
You can, but mixed numbers are usually preferred for area problems. square meters is easier to visualize than square meters.
Always include units! Since you're multiplying meters × meters, your answer must be in square meters. Area always has squared units.
Estimate first: is about 6, and is about 0.7, so 6 × 0.7 ≈ 4.2. Our answer ≈ 3.67 is close!
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