Calculate Cuboid Volume: Finding Volume in Terms of X with Dimensions (5+X, 4+X, 7)

Algebraic Expansion with Variable Dimensions

Look at the following cuboid.

Express the volume of the cuboid in terms of X.

AAABBBDDDCCCEEEGGGFFFHHH75+X4+X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:05 Let's express the box's volume using X.
00:08 We start with the formula for box volume.
00:12 It's height times length times width.
00:15 We'll substitute numbers to find the volume in terms of X, step by step.
00:33 Remember, open parentheses correctly. Multiply each term carefully.
00:58 Multiply each factor. Be sure to get every part.
01:18 And there you have it! That's how we find the solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the following cuboid.

Express the volume of the cuboid in terms of X.

AAABBBDDDCCCEEEGGGFFFHHH75+X4+X

2

Step-by-step solution

To solve this problem, we'll begin by writing down the formula for the volume of a cuboid. The volume V V is given by:

V=length×width×height V = \text{length} \times \text{width} \times \text{height}

Given dimensions are:

  • Length = 5+X 5 + X
  • Width = 4+X 4 + X
  • Height = 7 7

Substituting these into the formula gives:

V=(5+X)×(4+X)×7 V = (5 + X) \times (4 + X) \times 7

First, expand the product of the first two terms:

(5+X)(4+X)=5×4+5×X+X×4+X×X (5 + X)(4 + X) = 5 \times 4 + 5 \times X + X \times 4 + X \times X =20+5X+4X+X2 = 20 + 5X + 4X + X^2 =X2+9X+20 = X^2 + 9X + 20

Now multiply this by the height (7):

V=(X2+9X+20)×7 V = (X^2 + 9X + 20) \times 7 =7×X2+7×9X+7×20 = 7 \times X^2 + 7 \times 9X + 7 \times 20 =7X2+63X+140 = 7X^2 + 63X + 140

Thus, the volume of the cuboid in terms of X X is:

7X2+63X+140 7X^2 + 63X + 140

3

Final Answer

7x2+63x+140 7x^2+63x+140

Key Points to Remember

Essential concepts to master this topic
  • Volume Formula: Multiply length × width × height for cuboids
  • FOIL Method: (5+X)(4+X) = 20 + 5X + 4X + X² = X² + 9X + 20
  • Final Check: Multiply expanded result by height: 7(X² + 9X + 20) = 7X² + 63X + 140 ✓

Common Mistakes

Avoid these frequent errors
  • Adding dimensions instead of multiplying
    Don't add (5+X) + (4+X) + 7 = 16+2X! This gives perimeter, not volume. Volume requires space, so it needs multiplication. Always multiply all three dimensions: (5+X) × (4+X) × 7.

Practice Quiz

Test your knowledge with interactive questions

A rectangular prism has a base measuring 5 units by 8 units.

The height of the prism is 12 units.

Calculate its volume.

121212888555

FAQ

Everything you need to know about this question

Why do I expand (5+X)(4+X) first instead of multiplying by 7 immediately?

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It's easier to work with two variables at a time! Expanding (5+X)(4+X) first gives you X² + 9X + 20, then you just multiply this entire expression by 7. This prevents mistakes.

How do I remember the FOIL method correctly?

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FOIL stands for First, Outer, Inner, Last:

  • First: 5 × 4 = 20
  • Outer: 5 × X = 5X
  • Inner: X × 4 = 4X
  • Last: X × X = X²

Then combine: X² + 5X + 4X + 20 = X² + 9X + 20

What if X has a negative value? Will my volume be negative?

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Great question! For this to represent a real cuboid, all dimensions must be positive. This means X > -4 (so 4+X > 0) and X > -5 (so 5+X > 0). In practice, X would be positive.

Can I factor the final answer 7X² + 63X + 140?

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Yes! You can factor out 7: 7(X2+9X+20) 7(X^2 + 9X + 20) . You could even factor further: 7(X+4)(X+5) 7(X + 4)(X + 5) . Both forms are correct!

How do I check if 7X² + 63X + 140 is right?

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Pick a simple value for X, like X = 1. Your formula gives: 7(1)² + 63(1) + 140 = 210. Using dimensions directly: (5+1) × (4+1) × 7 = 6 × 5 × 7 = 210 ✓

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