Calculate Daily Meals: Solving 3 × 17 Multiplication Problem

Multiplication Word Problems with Daily Routines

Daniel prepares 3 meals every day.

How many meals does Daniel prepare in 17 days?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 How many meals does Danny prepare for 17 days?
00:03 Given: number of meals per day, number of days
00:08 We will use long multiplication to calculate
00:12 We will solve each multiplication separately and then substitute in the long multiplication
00:29 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Daniel prepares 3 meals every day.

How many meals does Daniel prepare in 17 days?

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the number of meals Daniel prepares per day, which is given as 3.
  • Step 2: Identify the total number of days, which is given as 17.
  • Step 3: Multiply the number of meals per day by the number of days to find the total meals.

Now, let's work through each step:
Step 1: Daniel prepares 3 3 meals per day.
Step 2: We are considering a total of 17 17 days.
Step 3: Calculate the total number of meals by multiplying:
Total meals=3×17\text{Total meals} = 3 \times 17

Carrying out the multiplication:
3×17=513 \times 17 = 51

Therefore, Daniel prepares a total of 51 51 meals over 17 days.

3

Final Answer

51 51

Key Points to Remember

Essential concepts to master this topic
  • Rule: Identify items per day and number of days
  • Technique: Multiply directly: 3 meals/day × 17 days = 51 meals
  • Check: Divide answer by days: 51 ÷ 17 = 3 meals/day ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of multiplying
    Don't add 3 + 17 = 20 meals! This only gives you meals for two days, not seventeen days. Always multiply when finding totals across multiple time periods.

Practice Quiz

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FAQ

Everything you need to know about this question

How do I know when to multiply instead of add?

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Look for repeated amounts over time! If someone does the same thing every day for multiple days, you multiply. Adding only works for one-time events.

What if the number of meals changes each day?

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If meals vary daily, you'd need to add each day's meals instead. But when it says "every day", the amount stays constant, so multiply!

Can I solve this problem differently?

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Yes! You could use repeated addition: 3+3+3... (17 times). But multiplication is much faster and less error-prone for larger numbers.

How do I check if 51 meals makes sense?

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Think about it: 3 meals per day for over two weeks should be around 40-60 meals. Since 51 51 falls in this range, it's reasonable!

What if I forgot how to multiply 3 × 17?

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Break it down! 3×17=3×(10+7)=30+21=51 3 \times 17 = 3 \times (10 + 7) = 30 + 21 = 51 . You can also use skip counting by 3s seventeen times.

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