Calculate the Sum: 36715 + 45192 in Vertical Format

36715+45192776 \begin{aligned} &36715\\ +& \\ &45192 \\ &\underline{\phantom{776}} & \\ \end{aligned}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Each time consider combining 2 digits, and then place
00:06 Let's start by combining ones with ones
00:09 Place the ones
00:12 Combine tens with tens
00:15 Place tens in tens, and add 1 to hundreds
00:20 Combine hundreds with hundreds, remember to add 1 to the calculation
00:24 Place in hundreds
00:27 Combine thousands with thousands
00:31 Place in thousands, add 1 to tens of thousands
00:36 Combine tens of thousands with tens of thousands, add 1 to the calculation
00:42 Place in tens of thousands
00:45 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

36715+45192776 \begin{aligned} &36715\\ +& \\ &45192 \\ &\underline{\phantom{776}} & \\ \end{aligned}

2

Step-by-step solution

To solve the problem effectively, we will follow a systematic approach:

  • Step 1: Write the two numbers one above the other, aligning by columns according to their place value.
  • Step 2: Begin adding from the rightmost column (the units place), moving leftward. Remember to carry over any tens to the next place value.
  • Step 3: Continue to add column by column, including any carries from the previous column.

Let's work through these steps with the given numbers:

+36715+45192 \begin{aligned} &\phantom{+}36715 \\ + &45192 \\ \hline \end{aligned}

Units Column (far right):
5 (from 36715) + 2 (from 45192) = 7

Tens Column:
1 (from 36715) + 9 (from 45192) = 10
Write down 0, and carry over 1.

Hundreds Column:
7 (from 36715) + 1 (carry) + 1 (from 45192) = 9

Thousands Column:
6 (from 36715) + 5 (from 45192) = 11
Write down 1, and carry over 1.

Tens of Thousands Column:
3 (from 36715) + 4 (from 45192) + 1 (carry) = 8

Thus, the sum is:

+36715+4519281907 \begin{aligned} &\phantom{+}36715 \\ + &45192 \\ \hline &81907 \\ \end{aligned}

Therefore, the solution to the problem is 81907 81907 .

3

Final Answer

81907

Practice Quiz

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\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)

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