Change one digit to make the number 2163 divisible by 4 without a remainder.
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Change one digit to make the number 2163 divisible by 4 without a remainder.
To solve the problem of making the number 2163 divisible by 4, we'll utilize the divisibility rule for 4, which states that a number is divisible by 4 if and only if the number formed by its last two digits is divisible by 4. Let's proceed with this approach:
First, let's identify the key information:
The number provided is 2163, and we need to change one digit so that it's divisible by 4. We are given multiple choice options that suggest switching different digits to achieve divisibility. Let's evaluate these choices based on the divisibility rule for 4.
Based on our analysis, the only configuration that makes the number divisible by 4 is 2136, achieved by switching the 3 and the 6. Hence, the correct answer according to the divisibility rule for 4 is to switch these two digits.
Therefore, the solution to the problem is Switch the 3 and the 6.
Switch the 3 and the 6
Is the number 43 divisible by 4?
This works because 100 is divisible by 4! Any number can be written as (hundreds × 100) + last two digits. Since 100 divides evenly by 4, only the last two digits determine if the whole number is divisible by 4.
You can change any digit, but changing the last two digits is usually easier! If 63 becomes 64 (divisible by 4), then 2163 becomes 2164 (also divisible by 4).
Use mental math: divide by 2 twice. For example, 64 ÷ 2 = 32, then 32 ÷ 2 = 16. Since 16 is a whole number, 64 is divisible by 4!
Yes! You could change 6 to make 2143 (43 isn't divisible by 4), or change 1 to make 2263 (63 still isn't divisible by 4). But changing 3 to 4 gives 2164, and 64 is divisible by 4.
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