Complete the Expression: (6×7×10) Raised to (y+4+a) Power

Power of Products with Variable Exponents

Insert the corresponding expression:

(6×7×10)y+4+a= \left(6\times7\times10\right)^{y+4+a}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 In order to open parentheses with a multiplication operation and an outside exponent
00:08 Raise each factor to the power
00:14 We will apply this formula to our exercise
00:17 Note that our power is actually the sum and the power (N)
00:21 Therefore we will raise each factor to this power
00:37 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(6×7×10)y+4+a= \left(6\times7\times10\right)^{y+4+a}=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify each factor inside the parentheses: 66, 77, and 1010.
  • Step 2: Use the power of a product rule, (abc)n=an×bn×cn(abc)^n = a^n \times b^n \times c^n, to distribute the exponent y+4+ay + 4 + a to each factor.
  • Step 3: Rewrite the expression with each base raised to the power of y+4+ay + 4 + a.

Now, let's work through each step:
Step 1: We have 6×7×106 \times 7 \times 10 as the base of the expression inside the parentheses.
Step 2: According to the power of a product rule, we distribute y+4+ay + 4 + a across each base, resulting in 6y+4+a×7y+4+a×10y+4+a6^{y+4+a} \times 7^{y+4+a} \times 10^{y+4+a}.
Step 3: Therefore, the expression (6×7×10)y+4+a(6 \times 7 \times 10)^{y+4+a} expands to 6y+4+a×7y+4+a×10y+4+a6^{y+4+a} \times 7^{y+4+a} \times 10^{y+4+a}.

Therefore, the solution to the problem is 6y+4+a×7y+4+a×10y+4+a 6^{y+4+a}\times7^{y+4+a}\times10^{y+4+a} .

3

Final Answer

6y+4+a×7y+4+a×10y+4+a 6^{y+4+a}\times7^{y+4+a}\times10^{y+4+a}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Distribute exponents to each factor in a product
  • Technique: Apply (abc)n=an×bn×cn (abc)^n = a^n \times b^n \times c^n to each base
  • Check: Each base gets same exponent: y+4+a y+4+a appears three times ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only one factor
    Don't write 6×7×10y+4+a 6 \times 7 \times 10^{y+4+a} = leaves 6 and 7 without exponents! This violates the power of a product rule. Always apply the exponent y+4+a y+4+a to every single factor inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does each number get the same exponent?

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Because of the power of a product rule! When you have (abc)n (abc)^n , the exponent applies to everything inside the parentheses equally. Think of it as multiplying the entire product by itself n n times.

What if the exponent was just a number like 3?

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The same rule applies! (6×7×10)3=63×73×103 (6 \times 7 \times 10)^3 = 6^3 \times 7^3 \times 10^3 . Whether the exponent is a number, variable, or expression like y+4+a y+4+a , distribute it to each factor.

Can I simplify the bases first, like 6×7×10 = 420?

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You could calculate 420y+4+a 420^{y+4+a} , but that's usually harder to work with! Keeping the factors separate as 6y+4+a×7y+4+a×10y+4+a 6^{y+4+a} \times 7^{y+4+a} \times 10^{y+4+a} is more useful for further calculations.

Does this work with addition inside parentheses too?

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No! This rule only works for multiplication. For example, (6+7)262+72 (6+7)^2 \neq 6^2 + 7^2 . Addition has different rules for exponents.

How do I remember this rule?

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Think: "Exponents are distributed to products, not sums." When you see multiplication inside parentheses with an exponent outside, give each factor the same exponent!

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