Complete the Expression: (9×2)^(3x) Mathematical Pattern

Power of Products with Variable Exponents

Insert the corresponding expression:

(9×2)3x= \left(9\times2\right)^{3x}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 In order to open parentheses with a multiplication operation and an outside exponent
00:08 Raise each factor to the power (N)
00:11 We will apply this formula to our exercise
00:14 Note that all the factors in the multiplication operation are raised to the same exponent (N)
00:17 Therefore, we will raise each factor to this power (N)
00:20 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(9×2)3x= \left(9\times2\right)^{3x}=

2

Step-by-step solution

To solve this problem, we'll apply the power of a product rule for exponents:

  • Identify that (9×2)3x(9 \times 2)^{3x} is a product of two numbers 99 and 22 raised to the same power 3x3x.
  • Apply the power of a product rule: (ab)n=an×bn(ab)^n = a^n \times b^n.
  • In our case, a=9a = 9, b=2b = 2, and n=3xn = 3x.
  • Thus, (9×2)3x=93x×23x(9 \times 2)^{3x} = 9^{3x} \times 2^{3x}.

Therefore, the expression (9×2)3x(9 \times 2)^{3x} simplifies to 93x×23x 9^{3x} \times 2^{3x} .

3

Final Answer

93x×23x 9^{3x}\times2^{3x}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Apply power to each factor: (ab)n=an×bn (ab)^n = a^n \times b^n
  • Technique: Distribute 3x to both 9 and 2: (9×2)3x=93x×23x (9×2)^{3x} = 9^{3x} \times 2^{3x}
  • Check: Verify using numerical values: if x=1, then (18)3=183 (18)^3 = 18^3

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only one factor
    Don't write (9×2)3x=9×23x (9×2)^{3x} = 9×2^{3x} = wrong distribution! This ignores the power rule and gives incorrect results. Always apply the exponent to each factor separately: 93x×23x 9^{3x} \times 2^{3x} .

Practice Quiz

Test your knowledge with interactive questions

\( (4^2)^3+(g^3)^4= \)

FAQ

Everything you need to know about this question

Why can't I just multiply 9×2 first to get 18?

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You could simplify to 183x 18^{3x} , but the question asks for the expanded form showing each base separately. Both 183x 18^{3x} and 93x×23x 9^{3x} \times 2^{3x} are mathematically equal!

Does the order matter in the final answer?

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No! Since multiplication is commutative, 93x×23x 9^{3x} \times 2^{3x} equals 23x×93x 2^{3x} \times 9^{3x} . Both orders are correct.

What if the exponent was just a number instead of 3x?

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The same rule applies! For example, (9×2)5=95×25 (9×2)^5 = 9^5 \times 2^5 . The power of a product rule works with any exponent, whether it's a number, variable, or expression.

How do I remember this rule?

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Think: "Power spreads to everyone!" When you have (ab)n (ab)^n , the exponent n gets distributed to both a and b, just like handing out the same thing to each person.

Can I use this rule backwards?

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Yes! If you see 93x×23x 9^{3x} \times 2^{3x} , you can factor it as (9×2)3x (9×2)^{3x} . This reverse application is called factoring out common exponents.

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