Complete the sequence:
1,113, 1,112, 1,111, …
The given sequence is 1113,1112,1111.
Let's analyze the sequence:
- The first term is 1113.
- The second term is 1112, which is 1113−1.
- The third term is 1111, which is 1112−1.
It's evident that each term is decreasing by 1 from the previous term. Therefore, this sequence is an arithmetic sequence with a common difference of −1.
Given this information, we can continue the sequence by subtracting 1 from the last given term, 1111.
- The next term is 1111−1=1110.
- Following that, 1110−1=1109.
- Finally, 1109−1=1108.
Thus, the next three terms in the sequence are 1110,1109, and 1108.
Looking at the provided options, choice 4: 1110,1109,1108, is the correct continuation of the sequence.
1,110, 1,109, 1,108