Is it possible for a cube to have a length equal to the diagonal of the face indicated in the figure?
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Is it possible for a cube to have a length equal to the diagonal of the face indicated in the figure?
To solve this problem, we will follow these steps:
Now, let's proceed through each step:
Step 1: For a cube with edge length , the face is a square with sides , and its diagonal can be found using the Pythagorean theorem:
Step 2: We consider if it is possible for the edge length to equal the diagonal. Thus, we set
Dividing both sides by , assuming , we get:
However, this is not correct since is not equal to . This shows that it is impossible for the edge length and the diagonal of the face to be equal.
Therefore, the solution to the problem is No.
No.
A cube has a total of 14 edges.
The diagonal cuts across the square face, creating the hypotenuse of a right triangle. By the Pythagorean theorem, the hypotenuse is always longer than either leg of the triangle.
is an irrational number that represents how much longer the diagonal is compared to the edge. Since it's greater than 1, the diagonal is always longer.
No! This specific relationship only applies to squares and cubes. Other shapes have different diagonal-to-side ratios.
Think of it this way: if you walk diagonally across a room, you travel farther than walking along the wall. The diagonal path is always longer than the straight edge!
A cube by definition has all edges equal. If edges were different lengths, it would be a rectangular prism, not a cube, and the problem would change completely.
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