Evaluate (11×5×4)/(9×13×17) Raised to the Eighth Power

Insert the corresponding expression:

(11×5×49×13×17)8= \left(\frac{11\times5\times4}{9\times13\times17}\right)^8=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to the power (N)
00:09 equals the numerator and denominator with the same power (N)
00:13 Note that both numerator and denominator are products
00:16 We will apply this formula to our exercise
00:27 According to the laws of exponents when a product is raised to the power (N)
00:31 it is equal to each factor in the product separately raised to the same power (N)
00:39 We will apply this formula to our exercise
01:00 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(11×5×49×13×17)8= \left(\frac{11\times5\times4}{9\times13\times17}\right)^8=

2

Step-by-step solution

To solve the problem, follow these steps:

  • Step 1: Use the property (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute the exponent 8 to both the numerator and the denominator.
  • Step 2: Raise each component in the numerator and the denominator to the power of 8.

Start by applying the rule to the entire fraction:

(11×5×49×13×17)8=(11×5×4)8(9×13×17)8 \left(\frac{11\times5\times4}{9\times13\times17}\right)^8 = \frac{(11\times5\times4)^8}{(9\times13\times17)^8}

Then apply the rule of powers to the product inside both the numerator and denominator:

=118×58×4898×138×178 = \frac{11^8 \times 5^8 \times 4^8}{9^8 \times 13^8 \times 17^8}

Therefore, the solution to the given problem is:

118×58×4898×138×178 \frac{11^8\times5^8\times4^8}{9^8\times13^8\times17^8}

3

Final Answer

118×58×4898×138×178 \frac{11^8\times5^8\times4^8}{9^8\times13^8\times17^8}

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\( (4^3)^2= \)

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