Evaluate (7×11×19)/(3×12×15) Raised to Power -6

Question

Insert the corresponding expression:

(7×11×193×12×15)6= \left(\frac{7\times11\times19}{3\times12\times15}\right)^{-6}=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:03 According to the laws of exponents, a fraction raised to a negative power (-N)
00:07 is equal to the reciprocal fraction raised to the positive power (N)
00:11 We will apply this formula to our exercise
00:15 We will convert to the reciprocal number and raise it to the opposite power
00:26 This is the solution

Step-by-Step Solution

To solve this problem, we'll apply the rules for negative exponents:

We start with the expression: (7×11×193×12×15)6 \left(\frac{7 \times 11 \times 19}{3 \times 12 \times 15}\right)^{-6} .

By the rule for negative exponents, (a/b)n=(b/a)n (a/b)^{-n} = (b/a)^n , we invert the fraction and change the exponent from 6-6 to 66:

(3×12×157×11×19)6 \left(\frac{3 \times 12 \times 15}{7 \times 11 \times 19}\right)^6

This transformation capitalizes on the idea that negative exponents reflect a reciprocal relationship.

Therefore, the expression with positive exponents is: (3×12×157×11×19)6 \left(\frac{3 \times 12 \times 15}{7 \times 11 \times 19}\right)^6 .

Answer

(3×12×157×11×19)6 \left(\frac{3\times12\times15}{7\times11\times19}\right)^6