Evaluate (7×11×19)/(3×12×15) Raised to Power -6

Question

Insert the corresponding expression:

(7×11×193×12×15)6= \left(\frac{7\times11\times19}{3\times12\times15}\right)^{-6}=

Video Solution

Solution Steps

00:13 Let's make this math problem simpler.
00:17 When a fraction is raised to a negative power, like negative N,
00:21 it's the same as the reciprocal of that fraction raised to positive N.
00:25 We'll use this idea in our exercise.
00:28 First, find the reciprocal, then use the opposite power.
00:39 And that's how we find the solution!

Step-by-Step Solution

To solve this problem, we'll apply the rules for negative exponents:

We start with the expression: (7×11×193×12×15)6 \left(\frac{7 \times 11 \times 19}{3 \times 12 \times 15}\right)^{-6} .

By the rule for negative exponents, (a/b)n=(b/a)n (a/b)^{-n} = (b/a)^n , we invert the fraction and change the exponent from 6-6 to 66:

(3×12×157×11×19)6 \left(\frac{3 \times 12 \times 15}{7 \times 11 \times 19}\right)^6

This transformation capitalizes on the idea that negative exponents reflect a reciprocal relationship.

Therefore, the expression with positive exponents is: (3×12×157×11×19)6 \left(\frac{3 \times 12 \times 15}{7 \times 11 \times 19}\right)^6 .

Answer

(3×12×157×11×19)6 \left(\frac{3\times12\times15}{7\times11\times19}\right)^6