Evaluate the Expression: Expanding (6×b)⁴

Power of Products with Exponent Distribution

Insert the corresponding expression:

(6×b)4= \left(6\times b\right)^4=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 In order to open parentheses with a multiplication operation and an outside exponent
00:07 We raise each factor to the power
00:13 We will apply this formula to our exercise
00:19 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(6×b)4= \left(6\times b\right)^4=

2

Step-by-step solution

The problem requires us to simplify (6×b)4(6 \times b)^4.

  • Step 1: Recognize that (6×b)(6 \times b) is a product of two factors 66 and bb.
  • Step 2: Apply the Power of a Product Rule, which states that (ab)n=an×bn(ab)^n = a^n \times b^n.

Let's apply this rule to (6×b)4(6 \times b)^4:
Using the rule, we distribute the exponent 44 to each component of the product:

(6×b)4=64×b4 (6 \times b)^4 = 6^4 \times b^4

Thus, the expression simplifies to 64×b46^4 \times b^4.

Therefore, the simplified expression is:

64×b46^4 \times b^4.

3

Final Answer

64×b4 6^4\times b^4

Key Points to Remember

Essential concepts to master this topic
  • Rule: Power of a product distributes to each factor
  • Technique: Apply exponent to both 6 and b: (6×b)4=64×b4 (6 \times b)^4 = 6^4 \times b^4
  • Check: Verify each factor has the same exponent as the original power ✓

Common Mistakes

Avoid these frequent errors
  • Only applying the exponent to one factor
    Don't write (6×b)4=64×b (6 \times b)^4 = 6^4 \times b or 6×b4 6 \times b^4 ! This ignores the power rule and gives an incomplete result. Always distribute the exponent to every factor inside the parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does the exponent 4 apply to both the 6 and the b?

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Because of the Power of a Product Rule! When you have (ab)n (ab)^n , the exponent n distributes to each factor, giving you an×bn a^n \times b^n . Think of it as multiplying the entire expression by itself 4 times.

What's the difference between 64×b4 6^4 \times b^4 and 6×b4 6 \times b^4 ?

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Huge difference! 64×b4=1296b4 6^4 \times b^4 = 1296b^4 while 6×b4=6b4 6 \times b^4 = 6b^4 . The first correctly applies the power rule, but the second misses the exponent on 6, making it much smaller.

Do I need to calculate 64 6^4 to get the final answer?

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Not necessarily! The expression 64×b4 6^4 \times b^4 is already simplified in its current form. You could calculate 64=1296 6^4 = 1296 to write 1296b4 1296b^4 , but both forms are correct.

Can this rule work with more than two factors?

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Absolutely! For example, (2×x×y)3=23×x3×y3 (2 \times x \times y)^3 = 2^3 \times x^3 \times y^3 . The exponent distributes to every single factor inside the parentheses, no matter how many there are.

What if there's a negative sign inside the parentheses?

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Great question! A negative sign acts like 1 -1 , so (6b)4=(1)4×64×b4=1×64×b4=64b4 (-6b)^4 = (-1)^4 \times 6^4 \times b^4 = 1 \times 6^4 \times b^4 = 6^4b^4 . Since (1)4=1 (-1)^4 = 1 , the result is positive!

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