Evaluate (x²-6)²: Solving a Perfect Square of a Binomial

Question

(x26)2= (x^2-6)^2=

Video Solution

Solution Steps

00:00 Simply
00:03 We'll use the shortened multiplication formulas to open the parentheses
00:12 In this case X squared is the A in the formula
00:19 In this case 6 is the B in the formula
00:27 Therefore, we'll substitute into the formula and solve
00:36 Let's calculate the multiplications
00:42 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify a and b in the expression (x26)2 (x^2 - 6)^2 .
  • Step 2: Apply the square of a difference formula.
  • Step 3: Simplify the resulting expression.

Now, let's work through each step:
Step 1: The expression is (x26)2 (x^2 - 6)^2 . Here, a=x2 a = x^2 and b=6 b = 6 .
Step 2: Apply the binomial formula: (ab)2=a22ab+b2 (a - b)^2 = a^2 - 2ab + b^2 .
Step 3:
1. Calculate a2 a^2 :
a2=(x2)2=x4 a^2 = (x^2)^2 = x^4 .
2. Calculate 2ab 2ab :
2ab=2(x2)(6)=12x2 2ab = 2(x^2)(6) = 12x^2 .
3. Calculate b2 b^2 :
b2=62=36 b^2 = 6^2 = 36 .
4. Substitute these back into the formula:
(x26)2=x412x2+36(x^2 - 6)^2 = x^4 - 12x^2 + 36.

Therefore, the expanded expression is x412x2+36 x^4 - 12x^2 + 36 .

Answer

x412x2+36 x^4-12x^2+36