Evaluate (x²-6)²: Solving a Perfect Square of a Binomial

Perfect Square Binomials with Higher Powers

(x26)2= (x^2-6)^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:03 We'll use the shortened multiplication formulas to open the parentheses
00:12 In this case X squared is the A in the formula
00:19 In this case 6 is the B in the formula
00:27 Therefore, we'll substitute into the formula and solve
00:36 Let's calculate the multiplications
00:42 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(x26)2= (x^2-6)^2=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify a and b in the expression (x26)2 (x^2 - 6)^2 .
  • Step 2: Apply the square of a difference formula.
  • Step 3: Simplify the resulting expression.

Now, let's work through each step:
Step 1: The expression is (x26)2 (x^2 - 6)^2 . Here, a=x2 a = x^2 and b=6 b = 6 .
Step 2: Apply the binomial formula: (ab)2=a22ab+b2 (a - b)^2 = a^2 - 2ab + b^2 .
Step 3:
1. Calculate a2 a^2 :
a2=(x2)2=x4 a^2 = (x^2)^2 = x^4 .
2. Calculate 2ab 2ab :
2ab=2(x2)(6)=12x2 2ab = 2(x^2)(6) = 12x^2 .
3. Calculate b2 b^2 :
b2=62=36 b^2 = 6^2 = 36 .
4. Substitute these back into the formula:
(x26)2=x412x2+36(x^2 - 6)^2 = x^4 - 12x^2 + 36.

Therefore, the expanded expression is x412x2+36 x^4 - 12x^2 + 36 .

3

Final Answer

x412x2+36 x^4-12x^2+36

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use (a - b)² = a² - 2ab + b² for binomial squares
  • Technique: Calculate (x²)² = x⁴, then 2(x²)(6) = 12x²
  • Check: Verify each term follows the pattern: x⁴ - 12x² + 36 ✓

Common Mistakes

Avoid these frequent errors
  • Treating x² as x when squaring
    Don't square (x²)² as x² = wrong power! This gives x² instead of x⁴ and completely changes the polynomial degree. Always remember that (x²)² = x⁴ when applying exponent rules.

Practice Quiz

Test your knowledge with interactive questions

Declares the given expression as a sum

\( (7b-3x)^2 \)

FAQ

Everything you need to know about this question

Why does (x²)² become x⁴ instead of x²?

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When you have exponents on exponents, you multiply them! So (x2)2=x2×2=x4 (x^2)^2 = x^{2 \times 2} = x^4 . Think of it as x² · x² = x⁴.

How do I remember the perfect square formula?

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Remember: First² - 2(First)(Last) + Last². The middle term is always twice the product of both terms, and it's negative when you have (a - b)².

What's the difference between (x² - 6)² and (x - 6)²?

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The first term changes everything! With (x² - 6)², you get x⁴ terms. With (x - 6)², you get x² terms. Always pay attention to what you're squaring.

Can I just multiply (x² - 6)(x² - 6) instead?

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Absolutely! That's actually what the perfect square formula represents. Use FOIL: First·First + Outer·Inner + Inner·Outer + Last·Last = x⁴ - 6x² - 6x² + 36 = x⁴ - 12x² + 36.

How do I check if my answer is right?

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You can factor your answer back to the original form! If x⁴ - 12x² + 36 factors to (x² - 6)², then you did it correctly.

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