Factorise the following expression:
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Factorise the following expression:
Let's factor the given expression:
This can be achieved by extracting the greatest common factor, both for numbers and letters.
We will address numbers and letters separately, remembering that a common factor is a factor (multiplier) that is common to all terms in the expression,
Let's start with the numbers:
Note that for the two numerical coefficients of the terms in the expression, namely the numbers 6 and 37, there is no single factor that is common to both. While the factors of the number 6 are the numbers 2 and 3 or 6 and 1. The number 37 is a prime number and therefore its only factors are 37 and 1, meaning - there is no factor that is common to these two numbers. Therefore - the number 1 (which is essentially the 0 power of any number - except 0) will be considered instead of the common factor for numbers.
For the letters:
There are two terms:
It's easy to see that there is no factor common to these two terms, Therefore there is no algebraic expression for letters that could be a common factor, meaning - the number 1 (which is essentially the 0 power of any number - except 0) will be considered instead of the common factor for letters.
This expression cannot be factored by extracting a common factor (or in any other way)
Therefore the correct answer is answer D.
Impossible
Break down the expression into basic terms:
\( 4x^2 + 6x \)
Look for the greatest common factor (GCF) of the coefficients first. For , the GCF of 37 and 6 is 1. Then check if variables share common factors - here a and b are different variables with no common factors.
37 is a prime number, meaning its only factors are 1 and 37. Since 6 = 2 × 3, there's no number (except 1) that divides both 37 and 6 evenly.
No! Factoring out a would give , but the second term 6b has no a to factor out. Same problem with factoring out b.
For simple expressions like this, common factoring is the only method. More complex techniques like grouping or special patterns don't apply to .
Yes! Not all expressions can be factored. In algebra, it's important to recognize when an expression is already in its simplest form. This is a valuable skill for more advanced math.
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