Identify All Divisors: Listing the Factors of 202

To solve this problem, we need to determine all factors of the number 202.

Step 1: Prime Factorization of 202
To find the prime factors of 202, we begin by dividing by the smallest prime number:

• $202 \div 2 = 101$

Step 2: Check if 101 is prime
101 cannot be divided evenly by any prime numbers up to its square root other than 1 and 101 itself. Therefore, 101 is a prime number.

Therefore, the prime factorization of 202 is $2 \times 101$.

Step 3: Listing factors
The factors of a number are all possible products of its prime factors, including 1 and the number itself.

• Starting with 1 (trivial factor) and ending with the number 202:
• Single prime 2 gives us two factors: $1$ and $2$.
• The factor 101 (as $101 \times 1$) is next.
• Combine $2$ and $101$ to get the factor $202$.

Therefore, the factors of 202 are: $1, 2, 101,$ and $202$.

In conclusion, after comparing with the provided choices, none of the exact choices given fully match as the factors of 202.