Identify the Number from Given Prime Factors: 2, 2, 5, and 11

Prime Factorization with Repeated Factors

What is the number whose prime factors are: 2,5,11,2 2,5,11,2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the number with the given prime factors
00:03 To find the number, multiply all factors together
00:07 Calculate one multiplication at a time and continue
00:22 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

What is the number whose prime factors are: 2,5,11,2 2,5,11,2

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Step-by-step solution

Let's tackle the problem of finding the number whose prime factors are 2,5,11, 2, 5, 11, and another 2 2 .

First, we need to understand what the problem is asking us to find. It describes a number that is completely defined by its prime factors, given by 2,5,11, 2, 5, 11, and another 2 2 . Essentially, we are tasked with determining the composite number that results from multiplying these prime factors together.

  • Step 1: Identify the given prime factors: 2,5,11, 2, 5, 11, and another 2 2 . This means we actually have 22×5×11 2^2 \times 5 \times 11 .
  • Step 2: Multiply the factors together to find the original number. We will break down the calculation for clarity:
    • First, calculate 22=4 2^2 = 4 .
    • Next, multiply this result by 5: 4×5=20 4 \times 5 = 20 .
    • Finally, multiply the previous result by 11: 20×11=220 20 \times 11 = 220 .

After performing these calculations, we find that the correct number is indeed 220.

Therefore, the solution to the problem is 220 220 .

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Final Answer

220 220

Key Points to Remember

Essential concepts to master this topic
  • Rule: Multiply all prime factors together to find original number
  • Technique: Group repeated factors: 2,2,5,11=22×5×11 2, 2, 5, 11 = 2^2 \times 5 \times 11
  • Check: Verify by dividing 220 by each prime factor completely ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of multiplying prime factors
    Don't add the prime factors 2 + 2 + 5 + 11 = 20! This gives a completely wrong result because prime factorization requires multiplication, not addition. Always multiply all prime factors together: 2×2×5×11=220 2 \times 2 \times 5 \times 11 = 220 .

Practice Quiz

Test your knowledge with interactive questions

Write all the factors of the following number: \( 5 \)

FAQ

Everything you need to know about this question

Why do I multiply the prime factors instead of adding them?

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Prime factorization means breaking a number into its prime building blocks. Just like 6 = 2 × 3, we multiply because that's how numbers are built from their prime parts!

What does it mean when a prime factor appears twice?

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When a prime appears multiple times (like two 2's), it means that prime has a power. So 2, 2 becomes 22=4 2^2 = 4 . Then multiply: 4×5×11=220 4 \times 5 \times 11 = 220 .

How can I check if 220 is really made of these prime factors?

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Divide 220 step by step:

  • 220 ÷ 2 = 110
  • 110 ÷ 2 = 55
  • 55 ÷ 5 = 11
  • 11 ÷ 11 = 1
You should end with 1 and use exactly the given primes!

Does the order of multiplication matter?

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No! You can multiply prime factors in any order due to the commutative property. Whether you do 2×2×5×11 or 11×5×2×2, you'll always get 220.

What if I made a calculation error?

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Double-check your arithmetic! Try calculating in steps: 22=4 2^2 = 4 , then 4×5=20 4 \times 5 = 20 , finally 20×11=220 20 \times 11 = 220 . Breaking it down prevents mistakes!

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