Listing All Factors: Discover Every Divisor of 720

To write all the factors of the number 720 using prime factorization, we will proceed as follows:

• Step 1: Start with the smallest prime number, 2, and divide 720 by 2.

$720 \div 2 = 360$

• Divide by 2 again.

$360 \div 2 = 180$

• Continue dividing by 2 until it no longer divides evenly.

$180 \div 2 = 90$

$90 \div 2 = 45$

• Step 2: Since 45 is not divisible by 2, move to the next prime number, which is 3.

$45 \div 3 = 15$

• Continue dividing by 3.

$15 \div 3 = 5$

• Step 3: Now divide by the next prime number, 5.

$5 \div 5 = 1$

The prime factorization of 720 is therefore:

$720 = 2^4 \times 3^2 \times 5^1$

Thus, the factors (including multiplicities) are:

$5,3,3,2,2,2,2$

Therefore, the solution to the problem is $5,3,3,2,2,2,2$.