Place Value Modification: Changing Digits in 429

Place Value Modifications with Digit Increases

If you increase the tens digit in the number 429 by 1 and the hundreds digit by 2, then what number are you left with?

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

If you increase the tens digit in the number 429 by 1 and the hundreds digit by 2, then what number are you left with?

2

Step-by-step solution

To solve this problem, we will modify the digits of the number 429 based on the given instructions:

  • Step 1: Identify the digits in the number 429. The hundreds digit is 4, the tens digit is 2, and the ones digit is 9.
  • Step 2: Increase the tens digit by 1. Therefore, the new tens digit is 2+1=3 2 + 1 = 3 .
  • Step 3: Increase the hundreds digit by 2. Therefore, the new hundreds digit is 4+2=6 4 + 2 = 6 .
  • Step 4: Construct the new number. The new number has a hundreds digit of 6, a tens digit of 3, and an unchanged ones digit of 9.

Therefore, the new number formed is 639 639 .

The correct answer to this problem is 639 639 , which matches choice 2.

3

Final Answer

639 639

Key Points to Remember

Essential concepts to master this topic
  • Rule: Identify each digit's place value position first
  • Technique: Add specified amounts: tens digit 2+1=3, hundreds digit 4+2=6
  • Check: Verify new number maintains correct place values: 6 hundreds, 3 tens, 9 ones = 639 ✓

Common Mistakes

Avoid these frequent errors
  • Adding to the wrong digit positions
    Don't confuse which digit is in which place value position = wrong final answer! Students often mix up tens and hundreds places. Always identify place values first: rightmost is ones, middle is tens, leftmost is hundreds.

Practice Quiz

Test your knowledge with interactive questions

What number do the blue squares below represent?

FAQ

Everything you need to know about this question

How do I remember which digit is in which place?

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Use the pattern: Hundreds-Tens-Ones from left to right. In 429, the 4 is hundreds (leftmost), 2 is tens (middle), and 9 is ones (rightmost).

What if adding makes a digit greater than 9?

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If any digit becomes 10 or more, you need to carry over to the next place value. For example, if tens digit becomes 12, write 2 in tens place and add 1 to hundreds place.

Can I change the ones digit too?

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Only change the digits mentioned in the problem! In this case, the ones digit stays the same at 9 because no change was requested for it.

How do I check my final answer?

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Compare each digit in your final number to what it should be: original + change = new digit. For 639: hundreds (4+2=6 ✓), tens (2+1=3 ✓), ones (9+0=9 ✓).

What's the easiest way to avoid mistakes?

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Write the original number with place value labels underneath:

  • 4 2 9
  • H T O
Then make your changes step by step and build the new number.

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