Place Value Problem: Finding a Number with Digits 2, 3, and 5 in Specific Positions

To solve this problem, we'll follow these steps:

• Step 1: Identify and place the known digits according to the decimal structure.
• Step 2: Determine if unspecified digits should be zeros, based on standard assumptions.
• Step 3: Construct the full number and compare it to given choices.

Now, let's walk through the solution:

Step 1: The problem provides several specific digits for different places in our number. Specifically, we know:
- The hundreds of thousands digit is $2$, so the number is of the form $200,000 + \ldots$.
- The thousands digit is $3$, making it $203,000 + \ldots$.
- The units digit is $5$, making the number complete to the form $203,005$.

Step 2: Since no other digit (specifically the ten-thousands place, hundreds, tens) is mentioned, we assume these are $0$. Therefore, the full number with respect to all place values would be $203,005$.

Step 3: The constructed number, based on provided conditions, is $203,005$. Let's match this against multiple-choice options:

• Option 1: $230,005$ does not match; the thousands digit should be $3$, not $30$.
• Option 2: Correctly matches as $203,005$.
• Option 3: $23,005$ is incorrect as it lacks tens of thousands and hundreds.
• Option 4: $2,305$ is a far lower number with misplaced significant digits.

Therefore, the solution to the problem, as per our analysis and matching of conditions, is $203,005$.