A frog jumps on the number axis.
It starts with the digit 1. It first jumps to a value equal to the value it is set to, divided by 3-.
Then it jumps to a value equal to the value at which it is placed, divided by +81.
Finally it jumps to a value equal to the value it is at, divided by 4-.
Where will you stop at the end of three jumps?
To solve this problem, we will perform each division in sequence as described:
Step 1: Initial Position
- The frog starts at x=1.
Step 2: First Jump
- Divide by −3:
x=−31=−31.
Step 3: Second Jump
- Divide by +81:
x=81−31=−31×8=−38.
Step 4: Third Jump
- Divide by −4:
x=−4−38=38×41=38×41=128=32.
Therefore, the frog stops at the position +32.