Simplify 1/(8⁻⁷ × 9⁻⁷ × 5⁻⁷): Negative Exponent Practice

Negative Exponent Rules with Multiple Terms

Insert the corresponding expression:

187×97×57= \frac{1}{8^{-7}\times9^{-7}\times5^{-7}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:12 Let's simplify this math problem, step by step.
00:16 If each factor in a product is raised to the same power, called N, we can rewrite it.
00:22 Put the entire product inside parentheses and raise it to the power of N. It's like magic!
00:28 Now, let's apply this idea to our exercise, and see how it works.
00:37 We'll use exponent laws to handle any negative exponents.
00:42 Remember, a negative exponent means we use the reciprocal of the number.
00:47 Let's apply this rule to our exercise as well.
00:50 Convert it to one divided by the number, then raise it to the positive power.
00:55 This step gets rid of the negative sign in the exponent.
00:59 And there you have it, our solution is complete!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

187×97×57= \frac{1}{8^{-7}\times9^{-7}\times5^{-7}}=

2

Step-by-step solution

To solve the problem, follow these steps:

  • Given the expression 187×97×57\frac{1}{8^{-7} \times 9^{-7} \times 5^{-7}}.
  • Apply the negative exponent rule: Each term in the denominator is raised to a negative power.
  • Write each term with positive exponents using the reciprocal rule: 1an=an\frac{1}{a^{-n}} = a^n.
  • This results in the expression: 87×97×578^7 \times 9^7 \times 5^7.
  • The power of a product rule tells us that this is equivalent to (8×9×5)7(8 \times 9 \times 5)^7.

Therefore, the solution is (8×9×5)7\left(8 \times 9 \times 5\right)^7.

Comparing with the multiple-choice options provided, the correct choice is: (8×9×5)7\left(8 \times 9 \times 5\right)^7.

3

Final Answer

(8×9×5)7 \left(8\times9\times5\right)^7

Key Points to Remember

Essential concepts to master this topic
  • Rule: Negative exponents in denominators become positive when moved to numerator
  • Technique: Convert 187 \frac{1}{8^{-7}} to 87 8^7 using reciprocal rule
  • Check: Use power of product rule: an×bn×cn=(a×b×c)n a^n \times b^n \times c^n = (a \times b \times c)^n

Common Mistakes

Avoid these frequent errors
  • Ignoring the fraction bar and treating negative exponents individually
    Don't work with 8^(-7) × 9^(-7) × 5^(-7) separately = gets messy fractions! This makes the problem much harder than needed. Always apply the reciprocal rule first: 1/(a^(-n)) = a^n for each term.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why does dividing by a negative exponent make it positive?

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Think of it as double negatives canceling out! When you have 1an \frac{1}{a^{-n}} , you're dividing by something that's already "flipped," so you flip it back to get an a^n .

Can I combine the numbers first, then apply the exponent?

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Yes! Since all terms have the same exponent (-7), you can use the power of a product rule: an×bn×cn=(abc)n a^n \times b^n \times c^n = (abc)^n . This makes calculations much easier!

What if the exponents were different numbers?

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If the exponents were different, you'd have to handle each term separately. But when they're the same (like -7 here), you can factor out the common exponent using product rules.

How do I know when to use the reciprocal rule?

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Use the reciprocal rule whenever you see negative exponents in a denominator. The pattern 1an=an \frac{1}{a^{-n}} = a^n always works and simplifies your work significantly!

Should I calculate 8 × 9 × 5 first?

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Not necessary! The question asks for the expression, not the final number. Leaving it as (8×9×5)7 (8 \times 9 \times 5)^7 shows you understand the concept and is the correct simplified form.

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