Simplify (3x)^8/(3x): Power and Division Expression

Exponent Division with Quotient Rule

(3×x)8(3×x) \frac{\left(3\times x\right)^8}{\left(3\times x\right)}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:03 Any number raised to the power of 1 equals itself
00:06 We'll use this formula in our exercise, and raise to the power of 1
00:11 We'll use the formula for dividing powers
00:13 Any number (A) to the power of (N) divided by the same base (A) to the power of (M)
00:16 equals the number (A) to the power of the difference of exponents (M-N)
00:18 We'll use this formula in our exercise
00:20 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(3×x)8(3×x) \frac{\left(3\times x\right)^8}{\left(3\times x\right)}

2

Step-by-step solution

Let's solve the expression (3×x)8(3×x) \frac{(3 \times x)^8}{(3 \times x)} step by step using the Power of a Quotient Rule for Exponents.

The expression given is:

(3×x)8(3×x) \frac{(3 \times x)^8}{(3 \times x)}

The Power of a Quotient Rule states that for any non-zero number a a , and integers m m and n n , the expression aman \frac{a^m}{a^n} is equal to amn a^{m-n} .

In this problem, a a is 3×x 3 \times x , m=8 m = 8 , and n=1 n = 1 .

Applying the Power of a Quotient Rule:

  • Subtract the exponent in the denominator from the exponent in the numerator. So we have (3×x)81 (3 \times x)^{8-1} .

Thus, the simplified form of the expression is:

(3×x)7 (3 \times x)^{7}

The solution to the question is: (3×x)7 (3 \times x)^{7} .

3

Final Answer

(3×x)81 \left(3\times x\right)^{8-1}

Key Points to Remember

Essential concepts to master this topic
  • Quotient Rule: When dividing powers with same base, subtract exponents
  • Technique: aman=amn \frac{a^m}{a^n} = a^{m-n} so (3x)8(3x)1=(3x)81 \frac{(3x)^8}{(3x)^1} = (3x)^{8-1}
  • Check: Final answer (3x)7 (3x)^7 has lower exponent than original numerator ✓

Common Mistakes

Avoid these frequent errors
  • Adding exponents instead of subtracting
    Don't add 8 + 1 = 9 to get (3x)9 (3x)^9 ! Addition is for multiplication of powers, not division. Always subtract the denominator exponent from numerator exponent when dividing.

Practice Quiz

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\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why do we subtract exponents when dividing?

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Think of it this way: x8x1 \frac{x^8}{x^1} means 8 copies of x divided by 1 copy of x. You cancel out 1 copy, leaving 8 - 1 = 7 copies, so x7 x^7 !

What if the denominator doesn't have an exponent showing?

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Any number or variable without a visible exponent actually has an exponent of 1. So (3x) (3x) is really (3x)1 (3x)^1 .

Can I cancel out the (3x) terms completely?

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No! You can't just cross out matching terms. You must use the quotient rule: subtract exponents when the bases are identical.

What happens if I get a negative exponent?

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If the denominator has a larger exponent than the numerator, you'll get a negative exponent. That's okay! an=1an a^{-n} = \frac{1}{a^n} .

How can I remember the quotient rule?

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Remember: "Same base, subtract the powers" - when dividing, you're taking away the bottom exponent from the top exponent.

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