Simplify (ab/xy)²: Squared Fraction Expression with Multiple Variables

Exponent Rules with Fraction Expressions

Insert the corresponding expression:

(a×bx×y)2= \left(\frac{a\times b}{x\times y}\right)^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:04 According to the laws of exponents, a fraction raised to the power (N)
00:08 equals the numerator and denominator raised to the same power (N)
00:12 We will apply this formula to our exercise
00:22 According to the laws of exponents when the entire product is raised to the power (N)
00:27 it is equal to each factor in the product separately raised to the same power (N)
00:33 We will apply this formula to our exercise
00:40 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(a×bx×y)2= \left(\frac{a\times b}{x\times y}\right)^2=

2

Step-by-step solution

Let's work through the solution step-by-step:

Step 1: Identify the expression
We are given the expression (a×bx×y)2\left(\frac{a \times b}{x \times y}\right)^2.

Step 2: Apply the power of a fraction rule
Using the rule (mn)p=mpnp\left(\frac{m}{n}\right)^p = \frac{m^p}{n^p}, we can rewrite the expression as:

(a×b)2(x×y)2\frac{(a \times b)^2}{(x \times y)^2}.

Which matches option 1.

Step 3: Apply the distributive property of exponents over multiplication
Using the rule (m×n)p=mp×np(m \times n)^p = m^p \times n^p, each part of the expression is expanded:

(a×b)2=a2×b2(a \times b)^2 = a^2 \times b^2 and (x×y)2=x2×y2(x \times y)^2 = x^2 \times y^2.

Thus, the expression becomes:

a2×b2x2×y2\frac{a^2 \times b^2}{x^2 \times y^2}.

Step 4: Identify the correct choice
Looking at the provided options, choice 3 is:

a2×b2x2×y2 \frac{a^2 \times b^2}{x^2 \times y^2} and option 1 is(a×b)2(x×y)2\frac{(a \times b)^2}{(x \times y)^2}

Both expression matches our derived solution, confirming that the correct answer is choice 4, A+C are correct.

3

Final Answer

A'+C' are correct

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} - apply exponent to numerator and denominator
  • Distributive Property: (xy)2=x2y2 (xy)^2 = x^2y^2 - each factor gets the exponent
  • Verification: Both (ab)2(xy)2 \frac{(ab)^2}{(xy)^2} and a2b2x2y2 \frac{a^2b^2}{x^2y^2} are correct forms ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only one factor
    Don't square just one variable like a2bx2y \frac{a^2b}{x^2y} = wrong answer! This ignores the distributive property of exponents. Always apply the exponent to every factor in both numerator and denominator.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why are both forms of the answer correct?

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Both (ab)2(xy)2 \frac{(ab)^2}{(xy)^2} and a2b2x2y2 \frac{a^2b^2}{x^2y^2} represent the same mathematical value! The first shows the exponent applied to grouped terms, while the second shows it distributed to individual factors.

Do I always have to expand the exponents?

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Not always! Sometimes leaving it as (ab)2(xy)2 \frac{(ab)^2}{(xy)^2} is perfectly acceptable. However, expanding to individual factors like a2b2x2y2 \frac{a^2b^2}{x^2y^2} often makes further calculations easier.

What if the exponent was 3 instead of 2?

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The same rules apply! (abxy)3=(ab)3(xy)3=a3b3x3y3 \left(\frac{ab}{xy}\right)^3 = \frac{(ab)^3}{(xy)^3} = \frac{a^3b^3}{x^3y^3} . Just remember to apply the exponent to every single factor.

How do I remember which variables get squared?

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Think of the exponent as a multiplier that affects everything inside the parentheses. Every variable in the numerator gets squared, and every variable in the denominator gets squared too!

Can I cancel terms before squaring?

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Be very careful! You can only cancel identical factors, and they must be in both numerator and denominator. It's often safer to apply the exponent first, then look for common factors to cancel.

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