Simplify the Expression: 6^(4x) ÷ 6^(x+1)

Quotient Rule with Variable Exponents

Insert the corresponding expression:

64x6x+1= \frac{6^{4x}}{6^{x+1}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:02 We'll use the formula for dividing powers
00:04 Any number (A) to the power of (N) divided by the same base (A) to the power of (M)
00:07 equals the number (A) to the power of the difference of exponents (M-N)
00:10 We'll use this formula in our exercise
00:12 Let's properly expand the parentheses
00:15 Negative times positive always equals negative
00:19 Let's group like terms
00:22 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

64x6x+1= \frac{6^{4x}}{6^{x+1}}=

2

Step-by-step solution

To solve the given expression 64x6x+1 \frac{6^{4x}}{6^{x+1}} , we must apply the Power of a Quotient Rule for Exponents. This rule states that aman=amn \frac{a^m}{a^n} = a^{m-n} .

Using this rule, the given expression can be rewritten as follows:

  • The numerator is 64x 6^{4x} .
  • The denominator is 6x+1 6^{x+1} .

Apply the Power of a Quotient Rule:

64x6x+1=64x(x+1) \frac{6^{4x}}{6^{x+1}} = 6^{4x - (x + 1)}

We need to simplify the exponent by performing the subtraction 4x(x+1) 4x - (x + 1) :

Step 1: Distribute the subtraction sign to the terms inside the parenthesis:

  • 4xx1 4x - x - 1

Step 2: Combine like terms:

  • 3x1 3x - 1

The expression simplifies to:

63x1 6^{3x-1}

Therefore, the solution to the question is: 63x1 6^{3x-1} .

3

Final Answer

63x1 6^{3x-1}

Key Points to Remember

Essential concepts to master this topic
  • Rule: For division of same bases, subtract exponents: a^m ÷ a^n = a^(m-n)
  • Technique: Carefully distribute negative sign: 4x - (x+1) = 4x - x - 1
  • Check: Verify by expanding: 6^(3x-1) = 6^4x ÷ 6^(x+1) when substituted ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute the negative sign in subtraction
    Don't write 4x - (x + 1) as 4x - x + 1 = 3x + 1! This gives the wrong exponent because you forgot the negative distributes to both terms. Always distribute the negative: 4x - (x + 1) = 4x - x - 1 = 3x - 1.

Practice Quiz

Test your knowledge with interactive questions

\( (3\times4\times5)^4= \)

FAQ

Everything you need to know about this question

Why do we subtract exponents when dividing powers with the same base?

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When you divide powers with the same base, you're essentially canceling out common factors. For example, 64÷62=6×6×6×66×6 6^4 ÷ 6^2 = \frac{6×6×6×6}{6×6} , and two 6's cancel out, leaving 62 6^2 . That's why we subtract: 4 - 2 = 2!

What if the exponent in the denominator is larger than in the numerator?

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No problem! You'll get a negative exponent. For example, 62÷65=625=63 6^2 ÷ 6^5 = 6^{2-5} = 6^{-3} . Remember that negative exponents mean the reciprocal: 63=163 6^{-3} = \frac{1}{6^3} .

How do I handle parentheses in the exponent subtraction?

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Always use the distributive property carefully! When you see 4x - (x + 1), the negative sign distributes to everything inside: 4xx1=3x1 4x - x - 1 = 3x - 1 . Don't forget that minus sign affects all terms!

Can I use this rule with different bases like 6^x ÷ 3^x?

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No! The quotient rule only works when the bases are identical. For 6x÷3x 6^x ÷ 3^x , you'd need to rewrite it as (6÷3)x=2x (6÷3)^x = 2^x using different rules.

What's the difference between 6^(3x-1) and 6^3x-1?

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The parentheses are crucial! 63x1 6^{3x-1} means the entire expression (3x-1) is the exponent. But 63x1 6^{3x} - 1 means you raise 6 to the 3x power, then subtract 1. Very different results!

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