Simplify the Expression: ax × 3ay × a2 × 2a Using Exponent Rules

Exponent Rules with Coefficient Multiplication

Simplify the following expression:

ax×3ay×a2×2a= a^x\times3a^y\times a^2\times2a=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following expression
00:03 When multiplying powers with equal bases
00:06 The power of the result equals the sum of the exponents
00:11 We'll apply this formula to our exercise and add together the exponents
00:19 Let's solve the multiplication of numbers
00:32 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Simplify the following expression:

ax×3ay×a2×2a= a^x\times3a^y\times a^2\times2a=

2

Step-by-step solution

Note that there is multiplication operation between all terms in the expression, hence we'll first apply the distributive property of multiplication in order to handle the coefficients of terms raised to powers, and the terms themselves separately. For greater clarity, let's break this down into steps:

ax3aya22a=32axaya2a=6axaya2a a^x\cdot3a^y\cdot a^2\cdot2a=3\cdot2\cdot a^x\cdot a^y\cdot a^2\cdot a=6\cdot a^x\cdot a^y\cdot a^2\cdot a

Due to the multiplication operation between all terms we could do this, it should be noted that we can (and it's preferable to) skip the middle step, meaning:

Write directly:ax3aya22a=6axaya2a a^x\cdot3a^y\cdot a^2\cdot2a=6\cdot a^x\cdot a^y\cdot a^2\cdot a

From here on we won't write the multiplication sign anymore instead we simply place the terms next to each other\ place the term next to its coefficient to indicate multiplication between them,

Proceed to apply the law of exponents for multiplication of terms with identical bases:

cmcn=cm+n c^m\cdot c^n=c^{m+n} Note also that this law applies to any number of terms being multiplied and not just two, for example for three terms with identical bases we obtain:

cmcnck=cm+nck=cm+n+k c^m\cdot c^n\cdot c^k=c^{m+n}\cdot c^k=c^{m+n+k}

Whilst we used law of exponents twice, we can also perform the same calculation for four terms or 5 and so on..,

Let's return to the problem, and apply the above law of exponents:

6axayaa2=6ax+y+2+1=6ax+y+3 6a^xa^yaa^2=6a^{x+y+2+1}=6a^{x+y+3}

Therefore the correct answer is d.

Important note:

Here we need to emphasize that we should always ask the question - what is the exponent being applied to?

For example, in this problem the exponent applies only to the bases of-

a a and not to the numbers, more clearly, in the following expression: 5c7 5c^7 the exponent applies only to c c and not to the number 5,

whereas when we write:(5c)7 (5c)^7 the exponent applies to each term of the multiplication inside the parentheses,

meaning:(5c)7=57c7 (5c)^7=5^7c^7

This is actually the application of the law of exponents:

(wr)n=wnrn (w\cdot r)^n=w^n\cdot r^n

which follows both from the meaning of parentheses and from the definition of exponents.

3

Final Answer

6a3+x+y 6a^{3+x+y}

Key Points to Remember

Essential concepts to master this topic
  • Exponent Rule: When multiplying powers with same base, add exponents
  • Coefficient Technique: Multiply coefficients separately: 3 × 2 = 6
  • Check: Count all terms: axaya2a1=ax+y+2+1 a^x \cdot a^y \cdot a^2 \cdot a^1 = a^{x+y+2+1}

Common Mistakes

Avoid these frequent errors
  • Applying exponents to coefficients
    Don't treat 3a² as (3a)² = 9a²! This applies the exponent to both coefficient and variable when it should only apply to the variable. Always keep coefficients separate from variables when applying exponent rules.

Practice Quiz

Test your knowledge with interactive questions

\( \)

Simplify the following equation:

\( 5^8\times5^3= \)

FAQ

Everything you need to know about this question

Why don't we apply the exponent to the coefficient?

+

The exponent only applies to what's directly attached to it. In 3a², the exponent 2 only applies to 'a', not to 3. If we meant both, we'd write (3a)² with parentheses.

How do I handle the plain 'a' term without an exponent?

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Remember that a = a¹! Every variable without a visible exponent has an implied exponent of 1. So when adding exponents, include +1 for each plain variable.

Can I multiply the coefficients and variables in any order?

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Yes! Multiplication is commutative, so you can rearrange terms. It's often easier to multiply coefficients first (3 × 2 = 6), then handle all the variable terms together.

What if there are different variables mixed together?

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Only combine powers with the same base. Variables like 'a' and 'b' stay separate. For example: 2a3b23ab4=6a4b6 2a^3b^2 \cdot 3ab^4 = 6a^4b^6

How do I remember to add all the exponents correctly?

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List each term's exponent clearly: x, y, 2, and 1 (for the plain 'a'). Then add them step by step: x + y + 2 + 1 = x + y + 3.

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