Simplify the Expression: Breaking Down 8y² into Basic Terms

Algebraic Expressions with Exponential Decomposition

Break down the expression into basic terms:

8y2 8y^2

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Break down the expression into basic terms:

8y2 8y^2

2

Step-by-step solution

To break down the expression 8y2 8y^2 , we identify the basic components. The expression y2 y^2 is a shorthand fory×y y \times y . Therefore, 8y2 8y^2 can be decomposed as 8yy 8 \cdot y \cdot y .

3

Final Answer

8yy 8\cdot y\cdot y

Key Points to Remember

Essential concepts to master this topic
  • Rule: Exponents represent repeated multiplication of the same factor
  • Technique: Break y2 y^2 into yy y \cdot y to show all factors
  • Check: Count factors: 8 (one factor) and y (two factors) = three total factors ✓

Common Mistakes

Avoid these frequent errors
  • Leaving exponents unchanged when breaking down expressions
    Don't write 8y2 8y^2 as 8y2 8 \cdot y^2 = still contains an exponent! This doesn't show the basic terms because y2 y^2 isn't broken down. Always expand exponents to show repeated multiplication: y2=yy y^2 = y \cdot y .

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 4x^2 + 6x \)

FAQ

Everything you need to know about this question

What does 'basic terms' mean in algebra?

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Basic terms are the simplest building blocks - just numbers and variables without exponents. Think of them as individual factors that multiply together to create the expression.

Why can't I just write 8 · y²?

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That still contains an exponent! The question asks for basic terms, which means breaking down y2 y^2 into yy y \cdot y to show all individual factors.

How do I know when an expression is fully broken down?

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An expression is fully broken down when it only contains numbers and single variables (no exponents). Each part should be a basic building block that can't be simplified further.

What if the exponent was higher, like y³?

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Same rule applies! y3 y^3 would become yyy y \cdot y \cdot y . The exponent tells you how many times to write the variable as a factor.

Does the order of factors matter?

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No! Due to the commutative property, 8yy 8 \cdot y \cdot y equals y8y y \cdot 8 \cdot y equals yy8 y \cdot y \cdot 8 . All arrangements give the same result.

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