Solve (2×3)/(7×9) Raised to the 7th Power: Complete Solution

Exponent Rules with Fraction Products

Insert the corresponding expression:

(2×37×9)7= \left(\frac{2\times3}{7\times9}\right)^7=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 According to the laws of exponents, a fraction raised to the power (N)
00:07 equals the numerator and denominator, each raised to the same power (N)
00:12 Note that both the numerator and denominator are products
00:16 We'll apply this formula to our exercise, making sure to use parentheses
00:23 According to the laws of exponents, a product raised to a power (N)
00:28 equals the product of each factor raised to that power (N)
00:32 We'll apply this formula to our exercise
00:39 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(2×37×9)7= \left(\frac{2\times3}{7\times9}\right)^7=

2

Step-by-step solution

To solve this problem, we'll rewrite the expression using the rules of exponents.

  • Step 1: Identify the initial expression as (2×37×9)7\left(\frac{2 \times 3}{7 \times 9}\right)^7.
  • Step 2: Apply the rule (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute the exponent of 7 to both the numerator and denominator.
  • Step 3: Rewrite the expression as (2×3)7(7×9)7\frac{(2 \times 3)^7}{(7 \times 9)^7}.
  • Step 4: Apply the exponent rule (ab)n=an×bn(ab)^n = a^n \times b^n to both the numerator and the denominator.

Following these steps, we can express:

(2×3)7(7×9)7=27×3777×97\frac{(2 \times 3)^7}{(7 \times 9)^7} = \frac{2^7 \times 3^7}{7^7 \times 9^7}.

Therefore, the correct answer is 27×3777×97\frac{2^7 \times 3^7}{7^7 \times 9^7}, which corresponds to choice 3.

3

Final Answer

27×3777×97 \frac{2^7\times3^7}{7^7\times9^7}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Distribute exponents to both numerator and denominator parts
  • Product Rule: (ab)n=an×bn (ab)^n = a^n \times b^n splits each factor
  • Check: Count factors: 27×37 2^7 \times 3^7 in numerator, 77×97 7^7 \times 9^7 in denominator ✓

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only some factors
    Don't write 2×377×97 \frac{2 \times 3^7}{7 \times 9^7} = wrong distribution! This violates the product rule by leaving some factors without exponents. Always apply the exponent to every single factor when distributing: (2×3)7=27×37 (2 \times 3)^7 = 2^7 \times 3^7 .

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just multiply 2×3 and 7×9 first, then raise to the 7th power?

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You absolutely can! (663)7=67637 \left(\frac{6}{63}\right)^7 = \frac{6^7}{63^7} gives the same result. However, the question asks for the expanded form showing all individual factors with their exponents.

What's the difference between the answer choices?

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Choice 1: Only applies exponent to 3 and 9, missing 2 and 7
Choice 2: Treats numerator as one unit but splits denominator
Choice 3: Correctly applies exponent to all four factors

Do I need to calculate the actual numerical answer?

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No! The question asks for the equivalent expression, not the final number. Keep it in the form 27×3777×97 \frac{2^7 \times 3^7}{7^7 \times 9^7} to show your understanding of exponent rules.

How do I remember which exponent rule to use?

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Think of it in two steps:
Step 1: (ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} (fraction rule)
Step 2: (xy)n=xnyn (xy)^n = x^n y^n (product rule)
Apply fraction rule first, then product rule to each part!

What if the numbers were different?

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The same rules apply! For any expression like (a×bc×d)n \left(\frac{a \times b}{c \times d}\right)^n , the answer is always an×bncn×dn \frac{a^n \times b^n}{c^n \times d^n} . Every factor gets the exponent!

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