+amp;66543amp;amp;52456amp;776amp;
Let's solve the problem step-by-step:
Step 1: Align the numbers for vertical addition as follows:
\begin{array}{c@{}c@{}c@{}c@{}c@{}c}
& 6 & 6 & 5 & 4 & 3 \\
+ & 5 & 2 & 4 & 5 & 6 \\
\hline
\end{array}
Step 2: Perform the addition from the rightmost digit (units place):
- Units place: 3+6=9
- Tens place: 4+5=9
- Hundreds place: 5+4=9
- Thousands place: 6+2=8
- Ten-thousands place: 6+5=11
- Write 1 in the ten-thousands place and carry over 1 to the next column.
- Since there are no more columns left to add the carry over, the final digit in the ten-thousands place is 11.
The final result is:
\begin{array}{c@{}c@{}c@{}c@{}c@{}c}
& 1 & 1 & 8 & 9 & 9 & 9 \\
\end{array}
Therefore, the sum of 66543 and 52456 is 118999.