We have hundreds of course questions with personalized recommendations + Account 100% premium
Let's solve the problem step-by-step:
Step 1: Align the numbers for vertical addition as follows:
\begin{array}{c@{}c@{}c@{}c@{}c@{}c} & 6 & 6 & 5 & 4 & 3 \\ + & 5 & 2 & 4 & 5 & 6 \\ \hline \end{array}
Step 2: Perform the addition from the rightmost digit (units place):
The final result is:
\begin{array}{c@{}c@{}c@{}c@{}c@{}c} & 1 & 1 & 8 & 9 & 9 & 9 \\ \end{array}
Therefore, the sum of 66543 and 52456 is .
118999
\( \begin{aligned} &83 \\ +& \\ &~~6 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write down the ones digit and 'carry' the tens digit to the next column to the left. For example: means write 1 and carry 1.
We start from the units place (rightmost) because any carrying affects the column to the left. Working left-to-right would mess up our carrying and give wrong answers!
That's totally normal! Just handle one column at a time. Add the digits in that column plus any carry from the previous column, then carry again if needed.
Try these methods:
That's expected when adding large numbers! The final answer 118999 has 6 digits while both original numbers had only 5 digits. This happens when there's a final carry.
Get unlimited access to all 18 Arithmetic Operations questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime