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To solve this problem, we'll apply the basic property of addition involving zero:
We start with the equation given in the problem:
Therefore, the solution to the problem is .
0
\( 1\times1000= \)
Think about it: if you already have 900, what do you need to add to still get 900? Nothing! Adding 0 keeps the number the same due to the identity property of addition.
Yes! Zero is a real number and a very important one. The identity property tells us that any number plus zero equals that same number.
Use inverse operations:
The same rule applies! Whatever number you're adding to itself, the missing addend is always 0. Try: 0 + 50 = 50 ✓
Absolutely! Besides substitution, think logically: "What plus 900 gives me 900?" Only zero makes sense because 900 is already the target number.
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