Solve for X: Perfect Square (x-4)² Equals Product (x+2)(x-1)

Quadratic Equations with Squared Binomials

Solve for x:

(x4)2=(x+2)(x1) (x-4)^2=(x+2)(x-1)

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:08 Let's find X.
00:12 We'll use the multiplication formulas to expand the parentheses.
00:16 Carefully open the parentheses. Multiply each term with every other term.
00:32 Now let's solve the multiplication and square any terms where needed.
00:40 Simplify by combining like terms.
00:46 Next, let's isolate the variable X.
01:10 And there you have it, that's the solution to our problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for x:

(x4)2=(x+2)(x1) (x-4)^2=(x+2)(x-1)

2

Step-by-step solution

Let's solve the equation, first we'll simplify the algebraic expressions using the extended distribution law:

(a+b)(c+d)=ac+ad+bc+bd (a+b)(c+d)=ac+ad+bc+bd We'll use the shortened multiplication formula for a squared binomial:

(a±b)2=a2±2ab+b2 (a\pm b)^2=a^2\pm2ab+b^2 We'll therefore apply the law and formula mentioned and open the parentheses in the expressions in the equation:

(x4)2=(x+2)(x1)x22x4+42=x2x+2x2x28x+16=x2+x2 (x-4)^2=(x+2)(x-1) \\ x^2-2\cdot x\cdot4+4^2=x^2-x+2x-2 \\ x^2-8x+16=x^2+x-2 We'll continue and combine like terms, by moving terms between sides - we can notice that the squared term cancels out and therefore it's a first-degree equation, which we'll solve by isolating the variable term on one side and dividing both sides of the equation by its coefficient:

x28x+16=x2+x29x=18/:(9)x=2 x^2-8x+16=x^2+x-2\\ -9x=-18\hspace{8pt}\text{/}:(-9)\\ \boxed{x=2} Therefore the correct answer is answer A.

3

Final Answer

x=2 x=2

Key Points to Remember

Essential concepts to master this topic
  • Expansion: Use (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 and FOIL method
  • Technique: (x4)2=x28x+16 (x-4)^2 = x^2 - 8x + 16 and (x+2)(x1)=x2+x2 (x+2)(x-1) = x^2 + x - 2
  • Check: Substitute x = 2: (24)2=4 (2-4)^2 = 4 and (2+2)(21)=4 (2+2)(2-1) = 4

Common Mistakes

Avoid these frequent errors
  • Incorrectly expanding the squared binomial
    Don't expand (x4)2 (x-4)^2 as x216 x^2 - 16 = missing the middle term! This forgets the -2ab term in the formula. Always use (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 to get x28x+16 x^2 - 8x + 16 .

Practice Quiz

Test your knowledge with interactive questions

Declares the given expression as a sum

\( (7b-3x)^2 \)

FAQ

Everything you need to know about this question

Why does the x² term cancel out on both sides?

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When you expand both sides, you get x28x+16=x2+x2 x^2 - 8x + 16 = x^2 + x - 2 . Since both sides have x2 x^2 , they cancel out when you subtract, leaving a linear equation!

How do I remember the squared binomial formula?

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Think "First squared, minus twice the product, plus last squared": (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 . Practice with simple examples like (x3)2 (x-3)^2 .

What's the FOIL method for (x+2)(x-1)?

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First: xx=x2 x \cdot x = x^2
Outer: x(1)=x x \cdot (-1) = -x
Inner: 2x=2x 2 \cdot x = 2x
Last: 2(1)=2 2 \cdot (-1) = -2
Combine: x2x+2x2=x2+x2 x^2 - x + 2x - 2 = x^2 + x - 2

Can I solve this without expanding everything?

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While expanding is the standard method, you could try substituting answer choices, but expanding helps you understand the algebra and works for any similar problem.

Why is the final answer x = 2 and not one of the other choices?

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After simplifying to 9x=18 -9x = -18 , divide both sides by -9 to get x=2 x = 2 . Always verify by substituting back into the original equation!

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