Solve log₇5 - log₇2: Base 7 Logarithm Subtraction

Logarithm Properties with Quotient Rule

log75log72= \log_75-\log_72=

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Step-by-step video solution

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00:00 Solve
00:09 We will use the formula for subtracting logarithms
00:17 Subtracting logarithms equals the logarithm of the quotient of numbers
00:24 We will use this formula in our exercise
00:34 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

log75log72= \log_75-\log_72=

2

Step-by-step solution

To solve the problem, let's use the rules of logarithms:

  • Step 1: Recognize that we are dealing with the subtraction of logarithms sharing the same base, which calls for the identity logbMlogbN=logb(MN)\log_b M - \log_b N = \log_b \left(\frac{M}{N}\right).
  • Step 2: Apply this identity to the expression log75log72\log_7 5 - \log_7 2.
  • Step 3: Realize that this can thus be expressed as a single logarithm: log7(52)\log_7 \left(\frac{5}{2}\right).
  • Step 4: Simplify the fraction, yielding log72.5\log_7 2.5.

Therefore, the simplification results in the expression: log72.5\log_7 2.5.

This matches the correct answer from the given choices.

3

Final Answer

log72.5 \log_72.5

Key Points to Remember

Essential concepts to master this topic
  • Rule: Subtraction of same-base logarithms becomes division inside logarithm
  • Technique: log75log72=log7(52) \log_7 5 - \log_7 2 = \log_7 \left(\frac{5}{2}\right)
  • Check: Verify 52=2.5 \frac{5}{2} = 2.5 matches the correct answer ✓

Common Mistakes

Avoid these frequent errors
  • Adding or multiplying the numbers inside instead of using quotient rule
    Don't calculate log₇5 - log₇2 as log₇3 or log₇10! This ignores the logarithm properties completely and gives wrong results. Always use the quotient rule: log_b M - log_b N = log_b(M/N).

Practice Quiz

Test your knowledge with interactive questions

\( \log_{10}3+\log_{10}4= \)

FAQ

Everything you need to know about this question

Why can't I just subtract 5 - 2 = 3 and write log₇3?

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Logarithms don't work like regular numbers! When you subtract logarithms with the same base, you're actually dividing the numbers inside. So log75log72=log7(52) \log_7 5 - \log_7 2 = \log_7 \left(\frac{5}{2}\right) , not log₇3.

What if the bases were different?

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You cannot use the quotient rule when bases are different! For example, log₇5 - log₂2 cannot be simplified this way. The quotient rule only works with identical bases.

How do I remember when to divide vs multiply inside the log?

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Think of it this way: Subtraction of logs = Division inside. Addition of logs = Multiplication inside. The operations are opposite!

Do I need to convert 2.5 to a fraction?

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Both log752 \log_7 \frac{5}{2} and log72.5 \log_7 2.5 are correct! Since 52=2.5 \frac{5}{2} = 2.5 , they're the same value. Use whichever form matches your answer choices.

Can I check this without a calculator?

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Yes! You can't easily find the numerical value of log₇2.5, but you can verify your algebra is correct. Check that 52=2.5 \frac{5}{2} = 2.5 and that you applied the quotient rule properly.

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