Solve: Product of Powers 20¹¹ × 4¹¹ × 2¹¹ × 5¹¹ × 3¹¹

Insert the corresponding expression:

2011×411×211×511×311= 20^{11}\times4^{11}\times2^{11}\times5^{11}\times3^{11}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 According to the power laws, a product raised to a power (N)
00:07 Equals a product where each factor is raised to that same power (N)
00:10 This formula is valid regardless of how many factors are in the product
00:25 We will apply this formula to our exercise
00:30 We'll break down the product into each factor separately raised to the power (N)
00:45 This is the solution

Step-by-step written solution

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1

Understand the problem

Insert the corresponding expression:

2011×411×211×511×311= 20^{11}\times4^{11}\times2^{11}\times5^{11}\times3^{11}=

2

Step-by-step solution

To solve this problem, we will use the rule of exponents which allows us to simplify expressions of the form an×bn=(a×b)na^n \times b^n = (a \times b)^n.

Here's how to simplify the expression step by step:

  • Step 1: Start with the original expression: 2011×411×211×511×311 20^{11} \times 4^{11} \times 2^{11} \times 5^{11} \times 3^{11} .

  • Step 2: Recognize that each term (20, 4, 2, 5, and 3) is raised to the power of 11, which allows the use of the product of powers rule. We can combine these bases into a single base raised to the common power: (20×4×2×5×3)11 (20 \times 4 \times 2 \times 5 \times 3)^{11}

Hence, the expression simplifies to (20×4×2×5×3)11 \left(20 \times 4 \times 2 \times 5 \times 3\right)^{11} , which corresponds to choice 3.

3

Final Answer

(20×4×2×5×3)11 \left(20\times4\times2\times5\times3\right)^{11}

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\( 112^0=\text{?} \)

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