Solve the Addition Equation: 1000 + □ = 1001

Addition Equations with Large Numbers

Complete the following equation:

1000+=1001 1000+\Box=1001

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Step-by-step written solution

Follow each step carefully to understand the complete solution
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Understand the problem

Complete the following equation:

1000+=1001 1000+\Box=1001

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Step-by-step solution

To solve the equation 1000+=1001 1000 + \Box = 1001 , we need to determine what number, when added to 1000, results in 1001.

Let's work through the solution with a simple subtraction method:

  • Step 1: We know that 1000+=1001 1000 + \Box = 1001 , and we need to find \Box.
  • Step 2: We can rearrange this equation to find \Box by subtracting 1000 from both sides of the equation. This gives:

=10011000 \Box = 1001 - 1000

  • Step 3: Perform the subtraction:

=1 \Box = 1

Therefore, the missing number is 1 1 .

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Final Answer

1 1

Key Points to Remember

Essential concepts to master this topic
  • Rule: Use subtraction to find the missing addend in equations
  • Technique: Transform 1000 + □ = 1001 into □ = 1001 - 1000
  • Check: Substitute back: 1000 + 1 = 1001 confirms our answer ✓

Common Mistakes

Avoid these frequent errors
  • Adding instead of subtracting to solve
    Don't try to find □ by doing 1000 + 1001 = 2001! This gives the wrong operation and a massive incorrect answer. Always subtract the known addend from the sum to find the missing addend.

Practice Quiz

Test your knowledge with interactive questions

Choose the correct answer:

\( 693+705=\text{ ?} \)

FAQ

Everything you need to know about this question

Why do I subtract 1000 from both sides?

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When you have 1000+=1001 1000 + \Box = 1001 , subtracting 1000 from both sides keeps the equation balanced. The left side becomes just \Box , and the right side becomes 10011000=1 1001 - 1000 = 1 .

How is this different from regular subtraction problems?

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In regular subtraction like 10011000 1001 - 1000 , you already know both numbers. Here, you're working backwards from an addition fact to find the missing piece!

What if the missing number was bigger?

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The method stays the same! For example, in 500+=1001 500 + \Box = 1001 , you'd calculate =1001500=501 \Box = 1001 - 500 = 501 . Always subtract the known addend from the sum.

Can I check my answer a different way?

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Yes! You can also think about it as: "What do I add to 1000 to get 1001?" Since 1000 and 1001 are consecutive numbers, the difference is always 1.

Why are the other answer choices wrong?

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  • 10: 1000 + 10 = 1010 (too big)
  • 100: 1000 + 100 = 1100 (way too big)
  • 1000: 1000 + 1000 = 2000 (much too big)

Only 1 gives us exactly 1001!

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