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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The problem involves an equation where .
Step 2: We know that the result of a division being zero () implies that the numerator must itself be zero — since any nonzero numerator would yield a nonzero quotient.
Step 3: Hence, we conclude that the unknown because the only value that satisfies the division condition of is if the numerator itself is zero.
Therefore, the solution to the problem is .
0
\( 1\times1000= \)
Great question! When we have , we're looking for what number divided by 70 gives us 0. Since 70 is positive, only zero divided by 70 can equal zero.
Let's check: , which is a small positive number, not zero. Only when the numerator is 0 does division result in 0.
Let's test it: , not 0. Remember, any number divided by itself equals 1, never 0.
Yes! Zero divided by any non-zero number always equals zero. So whenever you see , the answer is always 0!
That's undefined in mathematics! We can't divide zero by zero. But in our problem, we have , which is perfectly fine and equals 0.
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