Solve the Equation: -|3y²| with Negative Absolute Value

The absolute value of $3y^2$ is $3y^2$ itself because $3y^2$ is always non-negative regardless of the value of $y$ since any real number squared is non-negative. The negative sign outside the absolute value indicates that the expression$-\left|3y^2\right|$ evaluates to $-3y^2$.