Solve the Equation x² + 8² = 3x² + 16

Quadratic Equations with Algebraic Rearrangement

Solve the exercise:

x2+82=3x2+16 x^2+8^2=3x^2+16

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:06 Calculate 8 squared
00:13 Group factors
00:32 Isolate X
00:51 Take the root to find the solution
00:58 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the exercise:

x2+82=3x2+16 x^2+8^2=3x^2+16

2

Step-by-step solution

To solve this equation, we'll follow these steps:

  • Step 1: Understand and restate the problem.
  • Step 2: Rearrange the equation to group terms effectively.
  • Step 3: Solve for xx.

Now, let's work through each step:

Step 1: We begin with the equation x2+82=3x2+16 x^2 + 8^2 = 3x^2 + 16 . Our objective is to find the value(s) of x x that satisfy this equation. The equation is already composed of square terms and constants, providing a clue to equate similar terms and solve for x x .

Step 2: Let's rearrange the given equation:
\begin{align*} x^2 + 64 &= 3x^2 + 16 \end{align*}

Subtract x2 x^2 from both sides:
\begin{align*} 64 &= 3x^2 - x^2 + 16 \end{align*}

Which simplifies to:
\begin{align*} 64 &= 2x^2 + 16 \end{align*}

Next, subtract 16 from both sides:
\begin{align*} 64 - 16 &= 2x^2 \\ 48 &= 2x^2 \end{align*}

Now, divide both sides by 2 to further isolate x2 x^2 :
\begin{align*} 24 &= x^2 \end{align*}

Step 3: Solve for x x by taking the square root of both sides. Remember to consider both the positive and negative roots because squaring a number always yields a positive result:
\begin{align*} x &= \pm \sqrt{24} \end{align*}

Conclusion: The solutions to the equation are x=±24 x = \pm \sqrt{24} .

Therefore, the correct answer choice is: ±24 \pm \sqrt{24} .

3

Final Answer

±24 ±\sqrt{24}

Key Points to Remember

Essential concepts to master this topic
  • Principle: Group like terms by moving all variables to one side
  • Technique: Subtract x² from both sides: 64 = 2x² + 16
  • Check: Substitute x=24 x = \sqrt{24} : 24 + 64 = 72 + 16 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting the ± when taking square roots
    Don't write x = √24 only = missing half the solutions! Both positive and negative values of x will satisfy x² = 24 when squared. Always write x = ±√24 to capture both solutions.

Practice Quiz

Test your knowledge with interactive questions

Solve the following equation:


\( 2x^2-8=x^2+4 \)

FAQ

Everything you need to know about this question

Why do I need both positive and negative square roots?

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Because when you square any number, the result is always positive! Both (24)2=24 (\sqrt{24})^2 = 24 and (24)2=24 (-\sqrt{24})^2 = 24 . So both values satisfy the original equation.

Can I simplify √24 further?

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Yes! 24=4×6=26 \sqrt{24} = \sqrt{4 \times 6} = 2\sqrt{6} . So the final answer could also be written as ±2√6, but ±√24 is equally correct.

How do I know which terms to move to which side?

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Move all x² terms to one side and all constants to the other. This gives you the standard form x² = (number), making it easy to solve by taking square roots.

What if I get a negative number under the square root?

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Then the equation has no real solutions! You cannot take the square root of a negative number in real numbers. Always check your arithmetic if this happens.

Should I expand 8² first or leave it as is?

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Always expand numerical powers immediately! 82=64 8^2 = 64 makes the equation much clearer: x2+64=3x2+16 x^2 + 64 = 3x^2 + 16 .

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