Solve the Equation x² + 8² = 3x² + 16

Question

Solve the exercise:

x2+82=3x2+16 x^2+8^2=3x^2+16

Video Solution

Solution Steps

00:00 Solve
00:06 Calculate 8 squared
00:13 Group factors
00:32 Isolate X
00:51 Take the root to find the solution
00:58 And this is the solution to the question

Step-by-Step Solution

To solve this equation, we'll follow these steps:

  • Step 1: Understand and restate the problem.
  • Step 2: Rearrange the equation to group terms effectively.
  • Step 3: Solve for xx.

Now, let's work through each step:

Step 1: We begin with the equation x2+82=3x2+16 x^2 + 8^2 = 3x^2 + 16 . Our objective is to find the value(s) of x x that satisfy this equation. The equation is already composed of square terms and constants, providing a clue to equate similar terms and solve for x x .

Step 2: Let's rearrange the given equation:
\begin{align*} x^2 + 64 &= 3x^2 + 16 \end{align*}

Subtract x2 x^2 from both sides:
\begin{align*} 64 &= 3x^2 - x^2 + 16 \end{align*}

Which simplifies to:
\begin{align*} 64 &= 2x^2 + 16 \end{align*}

Next, subtract 16 from both sides:
\begin{align*} 64 - 16 &= 2x^2 \\ 48 &= 2x^2 \end{align*}

Now, divide both sides by 2 to further isolate x2 x^2 :
\begin{align*} 24 &= x^2 \end{align*}

Step 3: Solve for x x by taking the square root of both sides. Remember to consider both the positive and negative roots because squaring a number always yields a positive result:
\begin{align*} x &= \pm \sqrt{24} \end{align*}

Conclusion: The solutions to the equation are x=±24 x = \pm \sqrt{24} .

Therefore, the correct answer choice is: ±24 \pm \sqrt{24} .

Answer

±24 ±\sqrt{24}