Solve the exercise:
Solve the exercise:
To solve this equation, we'll follow these steps:
Now, let's work through each step:
Step 1: We begin with the equation . Our objective is to find the value(s) of that satisfy this equation. The equation is already composed of square terms and constants, providing a clue to equate similar terms and solve for .
Step 2: Let's rearrange the given equation:
\begin{align*}
x^2 + 64 &= 3x^2 + 16
\end{align*}
Subtract from both sides:
\begin{align*}
64 &= 3x^2 - x^2 + 16
\end{align*}
Which simplifies to:
\begin{align*}
64 &= 2x^2 + 16
\end{align*}
Next, subtract 16 from both sides:
\begin{align*}
64 - 16 &= 2x^2 \\
48 &= 2x^2
\end{align*}
Now, divide both sides by 2 to further isolate :
\begin{align*}
24 &= x^2
\end{align*}
Step 3: Solve for by taking the square root of both sides. Remember to consider both the positive and negative roots because squaring a number always yields a positive result:
\begin{align*}
x &= \pm \sqrt{24}
\end{align*}
Conclusion: The solutions to the equation are .
Therefore, the correct answer choice is: .