Solve the Equation: (x+7)(x-7)/3 = -11-x²

To solve the problem, begin with simplifying the left-hand side of the equation:

$(x+7)(x-7) = x^2 - 49$.

Thus, the original equation $\frac{(x+7)(x-7)}{3} = -11 - x^2$ simplifies to:

$\frac{x^2 - 49}{3} = -11 - x^2$.

Multiplying every term by 3 to clear the fraction, we obtain:

$x^2 - 49 = -33 - 3x^2$.

Add $3x^2$ to both sides to consolidate $x^2$ terms on one side:

$x^2 + 3x^2 = -33 + 49$.

This simplifies to:

$4x^2 = 16$.

Divide by 4 on both sides:

$x^2 = 4$.

Taking the square root of both sides provides:

$x = \pm 2$.

Therefore, the solution to the problem is $x = \pm 2$, corresponding to the choice labeled

±2

.