Solve the Inequality Puzzle: Finding Missing Digits in ?2?0 Between 7,590 and 9,001

To solve this problem, let's follow these steps:

• Step 1: Examine the tens digit.

• Step 2: Determine the thousands digit first.

• Step 3: Confirm that the number fits within the specified range.

Now, let's work through each step:

Step 1: Examine the tens-digit placeholder in $?2?0$. This number must be greater than 7,590. Therefore, the most significant digit, thousands' place, must be 8 or 9, because if it were 7, the last digit would need to be at least 6 (since 7,620 > 7,590, but 7,520 is not).

Step 2: Check thousands place digit choice:
- If the thousands digit is 9, the smallest number possible is 9,020, which is greater than 9,001 which does not fit.
- Thus, the thousands digit must be 8.

Step 3: Complete the number.
Given that the thousands digit is 8, verify:

• With the thousands digit as 8, $82?0$ is possible, align with the given range ensuring the complete number satisfies 7,590 < 8,2?0 < 9,001 .

Continue by recognizing only matching pairs from $8800$ to $8999$ apply to meet 7,590 < 8,2?0 < 9,001 .

Hence, the complete number is $8,280$.

Therefore, the solution to this problem is to fill the blanks with $8,8$.