We have hundreds of course questions with personalized recommendations + Account 100% premium
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The given equation is .
Step 2: According to the identity property of multiplication, for any number . Here, is 15.
Step 3: Therefore, the number that fulfills the equation must be 1. When 15 is multiplied by 1, it stays 15.
Therefore, the solution to the problem is .
1
\( 1\times1000= \)
Great question! While you see 15 on both sides, the missing factor isn't 15. Remember: , not 15. We need the number that keeps 15 unchanged when multiplied.
Only if the result is 0! Since any number times 0 equals 0, if you see , then the answer would be 0. But here we need .
The identity property says that any number multiplied by 1 stays the same: . The number 1 is called the multiplicative identity because it doesn't change other numbers.
Use the same thinking! Ask yourself: "What number times 7 gives me 7?" The answer is always 1 because of the identity property. Any number times 1 equals itself.
Yes! You can think: . Division and multiplication are opposite operations, so dividing both sides by 15 gives you the missing factor.
Get unlimited access to all 18 Order of operations for beginners questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime