Solve the Multiplication Equation: Finding the Factor in 15 × ? = 15

Identity Property with Missing Factor

15×?=15 15\times?=15

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Step-by-step video solution

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00:00 Solve
00:03 Any number multiplied by 1 is always equal to itself
00:09 And this is the solution to the question

Step-by-step written solution

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Understand the problem

15×?=15 15\times?=15

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Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the equation given which is 15×?=15 15\times?=15 .
  • Step 2: Apply the identity property of multiplication which tells us that any number multiplied by 1 is unchanged.
  • Step 3: Conclude that the unknown number should be 1, since 15×1=15 15 \times 1 = 15 .

Now, let's work through each step:

Step 1: The given equation is 15×?=15 15\times?=15 .

Step 2: According to the identity property of multiplication, a×1=a a \times 1 = a for any number a a . Here, a a is 15.

Step 3: Therefore, the number that fulfills the equation 15×?=15 15 \times ? = 15 must be 1. When 15 is multiplied by 1, it stays 15.

Therefore, the solution to the problem is 1 1 .

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Final Answer

1

Key Points to Remember

Essential concepts to master this topic
  • Identity Property: Any number multiplied by 1 equals itself
  • Technique: For 15 × ? = 15, the missing factor is 1
  • Check: Substitute back: 15 × 1 = 15 equals original result ✓

Common Mistakes

Avoid these frequent errors
  • Dividing to get zero as the answer
    Don't think 15 ÷ 15 = 0 means the missing factor is 0! Zero times anything equals zero, not 15. Always remember that 15 × 0 = 0, not 15, so use the identity property instead.

Practice Quiz

Test your knowledge with interactive questions

\( 1\times1000= \)

FAQ

Everything you need to know about this question

Why isn't the answer 15 since we see 15 on both sides?

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Great question! While you see 15 on both sides, the missing factor isn't 15. Remember: 15×15=225 15 \times 15 = 225 , not 15. We need the number that keeps 15 unchanged when multiplied.

Can the answer ever be 0 in multiplication problems like this?

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Only if the result is 0! Since any number times 0 equals 0, if you see 15×?=0 15 \times ? = 0 , then the answer would be 0. But here we need 15×?=15 15 \times ? = 15 .

What is the identity property of multiplication?

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The identity property says that any number multiplied by 1 stays the same: a×1=a a \times 1 = a . The number 1 is called the multiplicative identity because it doesn't change other numbers.

How do I solve similar problems like 7 × ? = 7?

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Use the same thinking! Ask yourself: "What number times 7 gives me 7?" The answer is always 1 because of the identity property. Any number times 1 equals itself.

Is there a division way to solve this?

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Yes! You can think: ?=15÷15=1 ? = 15 \div 15 = 1 . Division and multiplication are opposite operations, so dividing both sides by 15 gives you the missing factor.

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