Solve the Quadratic Equation: Find x in 4x² + 2x + 8 = x + 12 + x

Question

Solve the following equation:

4x2+8+2x=x+12+x 4x^2+8+2x=x+12+x

Video Solution

Solution Steps

00:08 Let's start by finding the value of X.
00:12 Now, gather all like terms together. This helps us to simplify.
00:21 Next, simplify everything as much as possible.
00:30 Let's isolate X on one side of the equation.
00:48 Great! Now, we need to extract the root.
00:52 Remember, when we extract a root, there are always two solutions: one positive and one negative.
00:59 And that gives us the solution to our problem!

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify both sides of the equation.
  • Step 2: Rearrange terms to form a quadratic equation.
  • Step 3: Solve the quadratic equation using an appropriate method, such as factoring or applying the quadratic formula.

Now, let's work through each step:

Step 1: Simplify both sides of the equation:

4x2+8+2x=x+12+x 4x^2 + 8 + 2x = x + 12 + x

The right-hand side can be simplified:

x+x+12=2x+12 x + x + 12 = 2x + 12

This yields the equation:

4x2+8+2x=2x+12 4x^2 + 8 + 2x = 2x + 12

Step 2: Rearrange the terms to form a quadratic equation. Subtract 2x+12 2x + 12 from both sides:

4x2+8+2x2x12=0 4x^2 + 8 + 2x - 2x - 12 = 0

Combining like terms gives:

4x24=0 4x^2 - 4 = 0

Step 3: Solve the resulting quadratic equation:

First, we add 4 to both sides:

4x2=4 4x^2 = 4

Next, divide both sides by 4:

x2=1 x^2 = 1

Now, apply the square root to both sides:

x=±1 x = \pm 1

Therefore, the solutions to the quadratic equation are

x=±1 x = \pm 1 .

The correct answer is choice 2: ±1.

Answer

±1