Solve the Quadratic Equation: -x² - 7x - 12 = 0

Quadratic Equations with Negative Leading Coefficients

Solve for x.

x27x12=0 -x^2-7x-12=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Multiply the entire exercise by minus to make it positive
00:15 Use trinomial to find the solution
00:19 Find 2 numbers whose product equals value C
00:23 And their sum equals value B
00:35 These are the matching numbers
00:45 Substitute these numbers in the trinomial
00:50 Find what zeros each factor
00:54 Isolate the unknown, this is one solution, now let's find the second
01:02 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for x.

x27x12=0 -x^2-7x-12=0

2

Step-by-step solution

First, factor using trinomials and remember that there might be more than one solution for the value of x x :

x27x12=0 -x^2-7x-12=0

Divide by -1:

x2+7x+12=0 x^2+7x+12=0

(x+3)(x+4)=0 (x+3)(x+4)=0

Therefore:

x+4=0 x+4=0

x=4 x=-4

Or:

x+3=0 x+3=0

x=3 x=-3

3

Final Answer

x=3,x=4 x=-3,x=-4

Key Points to Remember

Essential concepts to master this topic
  • Leading Coefficient: Divide by -1 to make the coefficient positive
  • Factoring: Find two numbers that multiply to 12 and add to 7
  • Check: Substitute x = -3: -(-3)² - 7(-3) - 12 = -9 + 21 - 12 = 0 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to divide the entire equation by -1
    Don't just factor -x² - 7x - 12 directly = impossible to factor correctly! The negative leading coefficient makes factoring much harder. Always divide every term by -1 first to get x² + 7x + 12 = 0.

Practice Quiz

Test your knowledge with interactive questions

Find the value of the parameter x.

\( 2x^2-7x+5=0 \)

FAQ

Everything you need to know about this question

Why do I need to divide by -1 first?

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Dividing by -1 makes the leading coefficient positive, which is the standard form for factoring. It's much easier to factor x2+7x+12 x^2 + 7x + 12 than x27x12 -x^2 - 7x - 12 !

How do I find the two numbers that work for factoring?

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You need two numbers that multiply to 12 and add to 7. Try factor pairs of 12: (1,12), (2,6), (3,4). Since 3 + 4 = 7, use 3 and 4!

What if I can't factor the quadratic?

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Not all quadratics can be factored easily! If factoring doesn't work, you can always use the quadratic formula: x=b±b24ac2a x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}

Why are both solutions negative?

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Look at the factored form: (x+3)(x+4)=0 (x+3)(x+4) = 0 . To make each factor zero, we need x = -3 and x = -4. Both solutions are negative because we're adding positive numbers to x to get zero.

How do I check my answers?

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Substitute each solution back into the original equation. For x = -3: (3)27(3)12=9+2112=0 -(-3)^2 - 7(-3) - 12 = -9 + 21 - 12 = 0

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