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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Adding Units
- Consider the rightmost column (units place). We add the digits: (from 156) and (from 254).
- .
- We write down in the units place and carry over to the tens place.
Step 2: Adding Tens
- Move to the next column on the left (tens place). We add the digits: (from 156), (from 254), plus the carry-over from the previous step.
- .
- We write down in the tens place and carry over to the hundreds place.
Step 3: Adding Hundreds
- Move to the hundreds column. We add the digits: (from 156), (from 254), plus the carry-over .
- .
- We write down in the hundreds place.
Putting it all together, the sum of .
Therefore, the solution to the problem is .
410
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Carrying happens when the sum in a column is 10 or more. Since each place value can only hold digits 0-9, we write the ones digit and carry the tens digit to the next column left.
Your final answer will be too small! For example, if you forget the carry in this problem, you'd get 400 instead of 410. Always double-check each column for carries.
Yes! Addition is commutative, meaning gives the same result as . The vertical format just makes carrying easier to track.
Try adding horizontally: . You can also estimate by rounding: , which matches our exact answer!
Same process! Just work column by column from right to left. Sometimes you might carry multiple times, but the steps stay the same: add the digits plus any carry, then carry again if needed.
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