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To solve this problem, let's perform vertical addition of the numbers 193 and 22:
Therefore, the sum of 193 and 22 is .
215
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write down the units digit and 'carry' the tens digit to the next column. For example: , so write 1 and carry 1.
Each column can only hold one digit! Writing 11 would mean you have 11 tens, which should actually be written as 1 hundred and 1 ten in separate columns.
Always start from the rightmost column (units place) and work your way left. This ensures you handle any carrying correctly as you move through each place value.
If one number doesn't have a digit in that place (like the hundreds place in 22), treat it as zero. So in the hundreds column: plus any carried digit.
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