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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We start by adding the digits in the ones place: . Since is greater than , we write down in the ones place and carry over to the tens place.
Step 2: Then, add the tens place digits. The tens digit of 45 is 4, and we add the carried over 1: .
Step 3: Therefore, after adding, the complete sum is .
Thus, the solution to the problem is , which corresponds to choice 4.
50
\( \begin{aligned} &83 \\ +& \\ &~~6 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Because 10 has two digits but the ones place can only hold one digit! The 0 stays in ones place, and the 1 moves to the tens place to show the correct value.
You'll get the wrong answer! For example, 5 + 5 = 10, but if you don't carry, you might write 410 instead of the correct answer 50.
Always carry to the left! Think of it like filling up containers - when the ones place is full (10), the extra goes to the bigger container (tens place).
Yes! Try counting up from the larger number: start at 45, then count 5 more: 46, 47, 48, 49, 50. You should get the same answer!
Like this problem where both end in 5! You'll often need to carry because 5 + 5 = 10, 7 + 7 = 14, etc. Just remember the carrying rule.
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