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To solve this problem, we'll follow these steps:
Step 1: Align the numbers 978 and 53 by their place value, where 53 is written below 978, making sure that the rightmost digits are in the same column. This means placing 978 over 53.
Align the numbers:
Step 2: Add the units place. Add 8 (from 978) and 3 (from 53). The sum is 8 + 3 = 11. Write 1 in the units place of the answer and carry over 1 to the tens place.
Step 3: Add the tens place. Add 7 (from 978) and 5 (from 53), also add the carryover of 1 from the previous step. The sum is 7 + 5 + 1 = 13. Write 3 in the tens place of the answer and carry over 1 to the hundreds place.
Step 4: Add the hundreds place. Add 9 (from 978) and the carryover 1 (from the tens calculation). The sum is 9 + 1 = 10. Write 0 in the hundreds place of the answer and carry over 1 to the thousands place.
Step 5: Since we have a carryover for the thousands place, write 1.
Thus, the complete sum is .
The solution to the problem is , which matches choice 2.
1031
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When you add digits and get a sum of 10 or more, you write the ones digit in that column and carry the tens digit to the next column on the left. For example, 8 + 3 = 11, so write 1 and carry 1.
Place value alignment ensures you're adding units to units, tens to tens, and hundreds to hundreds. If numbers aren't aligned, you'll add the wrong digits together and get an incorrect answer.
When one number is shorter (like 53 vs 978), treat the missing digits as zeros. So in the hundreds place, you're adding 9 + 0 + any carryover.
Use horizontal addition to verify: . You can also try adding in reverse order: . Both should give the same result!
Handle each carryover one column at a time. In this problem: units gives carryover 1, tens (7+5+1) gives carryover 1, hundreds (9+1) gives carryover 1 to thousands place.
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