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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Add the units digits. The units digit of 45 is 5, and the units digit of 77 is 7. Adding these gives: . Since 12 is greater than 9, we write down 2 in the units column and carry over 1 to the tens column.
Step 2: Add the tens digits. The tens digit of 45 is 4, and the tens digit of 77 is 7. Including the carry-over 1 gives: . Since 12 is a two-digit number, we write down 2 in the tens column and carry over 1 again, which is written in the hundreds column.
Step 3: Since there is nothing to add to the carried 1 in the hundreds column, we simply write it down as is.
Therefore, the solution to the problem is .
122
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write the units digit in that column and carry the tens digit to the next column. It's like breaking into !
Because each column can only hold one digit! Writing 12 would mean you have 12 units, but 10 units equals 1 ten. So you write 2 units and carry the 1 ten to the tens column.
That's totally normal! In this problem, we carried from units to tens (1), then from tens to hundreds (1). Just keep track of each carry-over as you work left.
Check your work by adding horizontally: . If it matches your column answer, you carried correctly! Also, make sure each column shows only one digit.
The final carry becomes a new digit in your answer! In this problem, the carry-over 1 becomes the hundreds digit, making our answer 122 instead of just 22.
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